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3 years ago

A Candy contains 300 pieces of which 28% are wet how many pieces are red

1 answer:

8 0

I assumed you meant red instead of wet.

To calculate this, multiply 28% (which is the same as .28) times 300.

300 x .28 = 84

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The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

Lerok [7]

$\Huge\bf{\underline{\red \dag { Aиѕωєя }}} \red \dag$

4 Packs of water and 7 Packs of candy bars.

So, we wanna know the smallest number that both 35 and 20 will go into.

Find the Least Common Multiple (LCM), but to find the LCM we need to find the prime factorization of each of the following number :-

$\sf {35 = 5(7)}$

$\sf \red {20 = 5(4)}$

$\sf {4 = 2(2)}$

$\sf \red {20 = 5(2)(2)$

~Now multiply all the numbers by 5 :-

$\sf \pink{5(7)(2)(2) = 35(2)(2) = 70(2) = 140}$

This means she needs 140 bottles of water and 140 candybars.

Water is sold in packs of 35, this means that she needs :

$\sf \orange{ \frac{140}{35} = 4\: packs \: of \: water}$

Candy bars are sold in packs of 20, this means she needs :

$\sf \green{ \frac{140}{20} = 7 \: packs \: of \: candy \: bars}$

_________________________

6 0

3 years ago

Tom finished 1/3 of the 30 problems assigned in class. Steven did 3/10 of the problems. Juan finished 20% of the problems. Marcu

RoseWind [281]

Answer: Tom

Step-by-step explanation:

Tom did 1/3 of 30= 10 out of 30

Steven did 3/10 of 30= 9 out of 30

Juan did 20/100 of 30= 6 out of 30

Marcus did 8 out of 30

6 0

3 years ago

Read 2 more answers

It took Mort one hour to ride 5 3/4 miles on his bicycle. How far will Mort be able to ride in 3 1/2 hours?

Simora [160]

Answer: The answer is 20 1/8.

8 0

3 years ago

Read 2 more answers

Can anyone help with this?

Mademuasel [1]

Answer:

error

Step-by-step explanation:

8 0

4 years ago

For the given angle 0, identify the reference angle, _

ankoles [38]

Answer:

π\6

Step-by-step explanation:

The reference angle is the smallest angle measured from the terminal side of the angle (where the angle ends) to the x axis. The reference angle is an acute angle (i.e less than 90° or π/2)

For O = 11π/6 = 1.833π

1.833π is in the fourth quadrant between 3π/2 radians and 2π radians. Since it is in the fourth quadrant, the reference angle is given as:

reference angle = 2π - 11π/6 = π\6

5 0

3 years ago