First, we establish
our hypothesis:
<span>Null hypothesis H0: μ = $1.00 </span>
Alternative hypothesis
Ha: μ ≠ $1.00
<span>Let’s say X = the sample average cost of a daily newspaper
= 0.96</span>
u = population mean
cost = 1.00
S = sample standard
deviation = 0.18
Calculating for z
value:
z = (X – u) / S
z = (0.96 – 1) / 0.18
z = – 0.222
From the standard
distribution table at this z value, p-value = 0.4129
Since alpha = 0.01,
the decision therefore is:
<span>Do not reject the null
hypothesis because the p-value is greater than 0.01. There is enough evidence
to support the claim that the mean cost of newspapers is $1. </span>
Answer:
A. m^2+7m+10=0
Step-by-step explanation:
This is a problem in pattern matching, and in substituting a variable for a pattern.
(x^2+3)^2 +7x^2 +21 = -10 . . . . . . given
(x^2 +3)^2 +7(x^2 +3) = -10 . . . . . factor the last two terms
m^2 +7m = -10 . . . . . . . . . . . . subsitute m for x^2 +3
m^2 +7m +10 = 0 . . . . . . . . add 10 to both sides; matches A
Answer: 5
Step-by-step explanation: I took the test
4 liters is slightly bigger
Answer:
x=0.59
Step-by-step explanation:
because if u divide 5.9 by 10 it will give u 0.59
and isolate x
