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Virty [35]
3 years ago
13

The sum of four consecutive odd integers is 216.find the four integer.

Mathematics
2 answers:
Alexus [3.1K]3 years ago
4 0
The four consecutive odd integers are x, x+2, x+4, x+6
x+x+2+x+4+x+6=216
4x+12=216
4x=204
x=51
they are 51, 53, 55, 57
Anuta_ua [19.1K]3 years ago
3 0
So what you want to say is 216/4, to find 1/4 of 216. 216 / 4 = 54

So you know that therefore, since 1/4 + 1/4 + 1/4 + 1/4 = 1, 54 + 54 + 54 + 54 must equal 216.

So basically what you can say is,  

x - 3 + x - 1 + x + 1 + x + 3 = 216

This would make them consecutive odd integers, but since the addition and subtractions cancel out, it would still make it equivalent.

Or basically:

(54 - 3) + (54 - 1) + (54 + 1) + (54 + 3) = 216

51 + 53 + 55 + 57

Those four integers would add up to 216, and would therefore be the four consecutive odd integers.
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Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

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Suma de perímetres = 162

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12x + 30 = 162

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Per tant,

Primer rectangle:

Amplada = 11

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2n rectangle:

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Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0
3 years ago
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julsineya [31]

Answer:

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Step-by-step explanation:

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3 years ago
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valina [46]
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