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Virty [35]
3 years ago
13

The sum of four consecutive odd integers is 216.find the four integer.

Mathematics
2 answers:
Alexus [3.1K]3 years ago
4 0
The four consecutive odd integers are x, x+2, x+4, x+6
x+x+2+x+4+x+6=216
4x+12=216
4x=204
x=51
they are 51, 53, 55, 57
Anuta_ua [19.1K]3 years ago
3 0
So what you want to say is 216/4, to find 1/4 of 216. 216 / 4 = 54

So you know that therefore, since 1/4 + 1/4 + 1/4 + 1/4 = 1, 54 + 54 + 54 + 54 must equal 216.

So basically what you can say is,  

x - 3 + x - 1 + x + 1 + x + 3 = 216

This would make them consecutive odd integers, but since the addition and subtractions cancel out, it would still make it equivalent.

Or basically:

(54 - 3) + (54 - 1) + (54 + 1) + (54 + 3) = 216

51 + 53 + 55 + 57

Those four integers would add up to 216, and would therefore be the four consecutive odd integers.
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Which expression is the completely factored form of x6−64y3 ?
ss7ja [257]

We are given this

x^6 -64y^3

write it as the difference of cubes

(x^2)^3 -(4y)^3

use the formula for the difference of cubes

(x^2-4y) ((x^2)^2+x^2*4y+(4y)^2)

Now use the formula for the difference of squares as 4y = (2\sqrt{y} )^2

(x-2\sqrt{y}) (x+2\sqrt{y}) (x^4+4x^2y+16y^2)

7 0
3 years ago
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Y=6<br> X+2y=16<br><br> Can someone one help me out its a substitution and system of equations graph
Nikitich [7]
If you know that y = 6. You just have to switch Y by 6.

x + 2y = 16
x + 2*6 = 16
x + 12 = 16
x = 16 - 12
x= 4

4 + 2*6 = 16

Hope this helps !

Photon
7 0
4 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
4 years ago
1 2/6 as an improper fraction
gladu [14]

Answer:

=4/3

Step-by-step explanation:

Step 1

Multiply the denominator by the whole number

6 × 1 = 6

Step 2

Add the answer from Step 1 to the numerator

6 + 2 = 8

Step 3

Write answer from Step 2 over the denominator

8/6

=86

You can also reduce this fraction.

Find the Greatest Common Factor (GCF) of 8 and 6, if it exists, and reduce our fraction by dividing both numerator and denominator by it,

GCF = 2

=8÷2=4

6/2=3

Simplified Solution

=6×1+2/6 =8/6=4/3

hope this helps

you welcome and thanks

3 0
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Dafna11 [192]

Step-by-step explanation:

-5x - 5y + 4x - (2y + 3)

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= - x - 5y - 2y - 3

= - x - 7y - 3 ( Answer )

5 0
3 years ago
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