if the smaller of two consecutive even intergers is subtracted from 3 times the larger the result is 42

1 answer:

3 0

<span>two consecutive even integers are x and x + 2
3(x + 2) - x = 42
3x + 6 -x = 42
2x = 36
x = 18
answer
smaller number: 18
bigger number: 18 + 2 = 20

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$\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}$

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$\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}$

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$m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}$