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N76 [4]
3 years ago
6

Roberto's toy car travels at 40 centimeters per second (cm/sec) at high speed and 25 cm/sec at low speed. If the car travels for

30 seconds at high speed and then 51 seconds at low speed, what distance would the car have traveled?
Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0

Answer:

2475 cm

Step-by-step explanation:

We are given that Roberto's toy car travels 40 cm/sec at high speed and 25 cm/sec at low speed.

We have to find that the distance would have the car traveled

Speed of car at high speed=40 cm/sec

Speed of car at low speed=25 cm/sec

If car  takes time to travel at high speed=30 seconds

If car takes time to travel  at low speed=51 seconds

Distance=speed\times time

Using this formula

Distance traveled by the car at high speed=40\times 30=1200 cm

Distance traveled by the car at low speed=51\times 25=1275 cm

Total distance traveled by the car =1200+1275=2475 cm

Hence, the distance  would have traveled by the car=2475 cm

Lesechka [4]3 years ago
3 0
HIGH SPEED= 40*30=1200 cm
low speed=  25*51=1275 cm 
total= 1200+1275=2475 cm
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