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nikitadnepr [17]
3 years ago
5

The alpha level that a researcher sets at the beginning of the experiment is the level to which he wishes to limit the probabili

ty of making the error of . Use the following Distributions tool to identify the boundaries that separate the extreme samples from the samples that are more obviously consistent with the null hypothesis. Assume the null hypothesis is nondirectional, meaning that the critical region is split across both tails of the distribution. The z-score boundaries at an alpha level α = .05 are: z = 1.96 and z = –1.96 z = 2.58 and z = –2.58 z = 3.29 and z = –3.29 To use the tool to identify the z-score boundaries, click on the icon with two orange lines, and slide the orange lines until the area in the critical region equals the alpha level. Remember that the probability will need to be split between the two tails. To use the tool to help you evaluate the hypothesis, click on the icon with the purple line, place the two orange lines on the critical values, and then place the purple line on the z statistic. The critical region is . The z-score boundaries for an alpha level α = 0.01 are: z = 3.29 and z = –3.29 z = 1.96 and z = –1.96 z = 2.58 and z = –2.58 Suppose that the calculated z statistic for a particular hypothesis test is 2.00 and the alpha is 0.01. This z statistic is the critical region. Therefore, the researcher reject the null hypothesis, and he conclude the alternative hypothesis is probably correct.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

Step-by-step explanation:

Hello!

Under the standard normal distribution, you have a two-tailed hypothesis set.

A hypothesis test is two-tailed means that the rejection region is divided into two equal areas in the tails of the distribution.

Under the null hypothesis curve, the "no rejection region" is the area "1-α" and "α" represents the rejection region, in this case, it is divided into two equal "tails" with is α/2

Generally speaking, you have two critical values that determine the tails of the rejection regions:

Lower critical value: Z_{\alpha/2 }

Upper critical value: Z_{1-\alpha /2}

1)

If you have a two-tailed hypothesis test with a significance level α: 0.05

The significance level will be divided into the two tails α/2: 0.025 and the critical values are defined as:

Z_{\alpha/2 }= Z_{0.025}= -1.965

Z_{1-\alpha /2}= Z_{0.975}= 1.965

(See first attachment for curves)

2)

In this item the hypotheses are two-tailed but the significance level is α: 0.01

Then the significance level will be divided into the two tails: α/2: 0.005

Z_{\alpha/2 }= Z_{0.005}= -2.586

Z_{1-\alpha /2}= Z_{0.995}= 2.586

(See second attachment for curves)

I hope it helps!

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Answer:

I think it's six

Step-by-step explanation:

A= 1

b= 2

c= 3

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3 years ago
what equation is solved by the graphed systems of equations? Two linear equations that intersect at the point negative 1, negati
alexgriva [62]

Answer:

1. The equation is solved by the graphed systems of equations is:

Third option: 7x + 3 = x − 3

2. The solution to the system is:

Fourth option: (3,-1)

3. The graph of the system y = −2x + 3 and 2x + 4y = 8 is:

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

4. The solution to the system is:

Second option: Infinite solutions.

5. Bill will have read the same amount of books as Mandy in:

Fourth option: December


Step-by-step explanation:

Question 1. What equation is solved by the graphed systems of equations?

Two linear equations that intersect at the point (-1, -4)=(x,y)→x=-1, y=-4

a. 7x + 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x+3-x

6x+3=3

Subtracting 3 both sides of the equation:

6x+3-3=3-3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

b. 7x − 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x-3-x

6x-3=-3

Adding 3 both sides of the equation:

6x-3+3=-3+3

6x=0

Dividing both sides of the equation by 6:

6x/6=0/6

Dividing:

x=0 different to the intersection at x=-1, then this is not the equation.

c. 7x + 3 = x − 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x+3-x=x-3-x

6x+3=-3

Subtracting 3 both sides of the equation:

6x+3-3=-3-3

6x=-6

Dividing both sides of the equation by 6:

6x/6=-6/6

Dividing:

x=-1 equal to the intersection at x=-1, then this is the equation.

d. 7x − 3 = x + 3

Solving for x: Grouping the x's on the left side of the equation: Subtracting x both sides of the equation:

7x-3-x=x+3-x

6x-3=3

Adding 3 both sides of the equation:

6x-3+3=3+3

6x=6

Dividing both sides of the equation by 6:

6x/6=6/6

Dividing:

x=1 different to the intersection at x=-1, then this is not the equation.


Question 2 (Multiple Choice Worth 2 points) (06.03) Solve the system 2x + 3y = 3 and 3x − 2y = 11 by using graph paper or graphing technology. What is the solution to the system?

The solution to the system is (3, -1) Fourth option

Please, see the attached graph.


Question 3 (Multiple Choice Worth 2 points) (06.03) What is the graph of the system y = −2x + 3 and 2x + 4y = 8?

Third option: Line through point (0, 3) and (1, 1). Line through (0, 2) and (4, 0).

Please, see the attached graph.


Question 4 (Multiple Choice Worth 2 points) (06.03) Solve the system y = 3x + 2 and 3y = 9x + 6 by using graph paper or graphing technology. What is the solution to the system?

Second option: Infinite solutions.

Please, see the attached graph.

Question 5 (Multiple Choice Worth 2 points) (06.03) At the end of April, Mandy told Bill that she has read 16 books this year and reads 2 books each month. Bill wants to catch up to Mandy. He tracks his book reading with a table on his door. Using his table below, what month will Bill have read the same amount of books as Mandy?

Bill

Month     Books

May             4

June            8

July             12

August        16

September 20

October      24

November  28

December  32


Books read by Mandy: y=16+2x

Numbers of months since april: x


May: x=1→y=16+2(1)=16+2→y=18 different to 4 (books read by Bill)

June: x=2→y=16+2(2)=16+4→y=20 different to 8 (books read by Bill)

July: x=3→y=16+2(3)=16+6→y=22 different to 12 (books read by Bill)

September: x=5→y=16+2(5)=16+10→y=26 different to 20 (books read by Bill)

October: x=6→y=16+2(6)=16+12→y=28 different to 24 (books read by Bill)

November: x=7→y=16+2(7)=16+14→y=30 different to 28 (books read by Bill)

December: x=8→y=16+2(8)=16+16→y=32 equal to 32 (books read by Bill)

Answer. Fourth option: December

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3 years ago
Which is the standard form of the equation of the parabola shown in the graph?
djverab [1.8K]

Answer:

B

Step-by-step explanation:

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Is the graph a linear function, nonlinear function, or Relation ( non-function) ?
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Answer:

A

Step-by-step explanation:

Because each value of x maps onto only one value of y, it is a function.

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There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc
sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and  B be the event that student play soccer.

P(A)=8\%

P(B)=14\%

It is given that 6 students play on both teams.

P(A\cap B)=\frac{6}{200}\times 100=3\%

We have to find the probability that a student plays either basketball or soccer.

P(A\cup B)=P(A)+P(B)-(A\cap B)

P(A\cup B)=8\%+14\%-3\%

P(A\cup B)=19\%

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

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