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Xelga [282]
3 years ago
7

Determine if the two triangles are congruent. If they are, state how you know

Mathematics
1 answer:
Alborosie3 years ago
5 0
<h3>Answers:</h3>
  1. Congruent by SSS
  2. Congruent by SAS
  3. Not congruent (or not enough info to know either way)
  4. Congruent by SAS
  5. Congruent by SSS
  6. Not congruent (or not enough info to know either way)
  7. Congruent by SAS
  8. Congruent by SAS

==================================

Explanations:

  1. We have 3 pairs of congruent sides. The tickmarks tell us how the congruent sides pair up (eg: the double tickmarked sides are the same length). So that lets us use SSS. The shared overlapping side forms the third pair of congruent sides.
  2. We have two pairs of congruent sides (the tickmarked sides and the overlapping sides), and an angle between the sides mentioned. Therefore, we can use SAS to prove the triangles congruent.
  3. We don't have enough info here. So the triangles might be congruent, or they might not be. The convention is to go with "not congruent" until we have enough evidence to prove otherwise.
  4. We can use SAS like with problem 2. Vertical angles are always congruent.
  5. This is similar to problem 1, so we can use SSS here.
  6. There isn't enough info, so it's pretty much a repeat of problem 3
  7. Same idea as problem 4.
  8. Similar to problem 2. We have two pairs of congruent sides and an included angle between them allowing us to use SAS

The abbreviations used were:

  • SSS = side side side
  • SAS = side angle side

The order is important with SAS because the angle needs to be between the sides mentioned.

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The width of a rectangle is 6 kilometers less than twice its length. if its area is 108 square​ kilometers, find the dimensions
Art [367]
Hi there!

Answer:
length = 9 kilometres
Width = 12 kilometres

Let's solve this problem step by step!
To find our answer we need to set up and solve an equation.

Let the length of the rectangle be represented by x.
The width of the rectangle can therefore be expressed by 2x - 6.

The area of a rectangle can be found by using the formula:
A = width × length

Plug in the data from the formula
A = x (2x - 6).

Simplify using rainbow technique.
x(2x - 6) = 2 {x}^{2} - 6x

Now we've found the simplified expression that expresses the area of the rectangle. Therefore, we can now set up and start solve the equation.

2 {x}^{2} - 6x = 108
Subtract 108

2 {x}^{2} - 6x - 108 = 0
Divide by 2.

{x}^{2} - 3x - 54
(x - 9)(x + 6) = 0
Rule AB = 0, gives A is 0 or B is 0.

x - 9 = 0 \\ x = 9 \\ \\ x + 6 = 0 \\ x = - 6

The length of the rectangle, which was represented by x, must be 9 (since it cannot be a negative number).

Length
x = 9
Width
2x - 6 = 2 \times 9- 6 = 18 - 6 = 12

Answer:
length = 9 kilometres
Width = 12 kilometres

~ Hope this helps you!
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3 years ago
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leonid [27]

Answer:78.4

Step-by-step explanation:

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Read 2 more answers
Three right triangles are drawn in the coordinate plane,
SashulF [63]

Answer:

Triangle A:

- smaller leg = 3

- longer leg = 10

- hypotenuse = 10.4

Traingle B:

- smaller leg = 4

- longer leg = 13

- hypotenuse = 13.6

Triangle C:

- smaller leg = 5

- longer leg = 7

- hypotenuse = 8.6

Step-by-step explanation:

Let's find the distance of the legs for the 3 right triangles.

<u>Triangle A</u>

The smaller leg (SL) is from (2,5) to (2,8), so the length is given by the distance in the y-axis:

SL_{A} = 8 - 5 = 3

Hence, the lenght of the smaller leg is 3.

The longer leg (LL) is from (-8, 8) to (2, 8), so the length is given by the distance in the x-axis:

LL_{A} = 2 - (-8) = 10

Then, the length of the longer leg is 10.  

Now, we can find the hypotenuse (H) by using Pitagoras:

H_{A} = \sqrt{SL_{A}^{2} + LL_{A}^{2}} = \sqrt{3^{2} + 10^{2}} = 10.4

<u>Triangle B</u>

The SL is from (3, -9) to (7, -9)

The length of the SL is:

SL_{B} = 7 - 3 = 4

The LL is from (7, -9) to (7, 4)

The length of the LL is:

LL_{B} = 4 - (-9) = 13

The hypotenuse is:

H_{B} = \sqrt{4^{2} + 13^{2}} = 13.6

<u>Triangle C</u>

The SL is from (-10, -6) to (-10, -1)

The length of the SL is:

SL_{C} = -1 - (-6) = 5

The LL is from (-10, -6) to (-3, -6)  

The length of the LL is:

LL_{C} = -3 - (-10) = 7

The hypotenuse is:

H_{C} = \sqrt{5^{2} + 7^{2}} = 8.6

I hope it helps you!

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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