We have been given for a normal distribution the mean time it takes to walk to the bus stop is 8 minutes with a standard deviation of 2 minutes. And the mean time it takes for the bus to get to school is 20 minutes with a standard deviation of 4 minutes.
(a) Average time that it would take reach school can be obtained by adding the average times.
8+20 = 28 minutes.
(b) Standard deviation of the trip to school can be found as:

Therefore, standard deviation of the entire trip is 4.47 minutes.
(c) Let us first find z score corresponding to 30 minutes.
We need to find the probability such that 
Therefore, the required probability is 0.67.
(d) If average time to walk to school is 10 minutes, then overall average time for the trip will be 10+20 = 30 minutes.
(e) Standard deviation won't change it will remain 4.47
(f) The new probability will be:


Therefore, probability will be 0.50.
The answer would be D.
Randall should choose the rebate offer because the shoes will be $2.40 less than if he chooses the sale price.
88 - 20% = 70.4
88 - 20 = 68
70.4 - 68 = 2.4 (2.40)
Please mark me brainliest! Thanks!
Answer: 
Step-by-step explanation:

There aren't any answer options so I will just simplify the expression:
10(2p+q)
20p+10q
Answer:
30 students
Step-by-step explanation:
80% of N = 24 where N is the total number of students
So
.80 N = 24
N = 24 / .80 = 30
sorry this was a late response