Answer:
1 "The product of two irrational numbers is SOMETIMES irrational." The product of two irrational numbers, in some cases, will be irrational. However, it is possible that some irrational numbers may multiply to form a rational product.
2 The quotient has widespread use throughout mathematics, and is commonly referred to as a fraction or a ratio. For example, when dividing twenty (the dividend) by three (the divisor), the quotient is six and two thirds. In this sense, a quotient is the ratio of a dividend to its divisor.
3 The sum of two irrational numbers, in some cases, will be irrational. However, if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational. "The product of two irrational numbers is SOMETIMES irrational."
Step-by-step explanation:
To arrange in descending order or greatest to least, we will first convert all the values in same unit.
Lets convert all the values in kg
1 lb = 0.45 kg
2 lb =
kg
1 g = 0.001 kg
891 g =
kg
1 T = 907.185 kg
0.02 T =
kg
Hence all values in kg becomes = 0.90 kg , 0.891 kg , 1 kg , 18.14 kg
So in descending order the values become
0.02T, 1 kg, 2 lb, 891 g
Answer:
Y= x+2 " substituting value of y
Step-by-step explanation:
Y=5x-4y = 5x - 4
or, 5x - 4(x+2) = 5x - 4
or, 5x - 4x+ 8 = 5x-4
or, x +8 = 5x - 4
or, 0= 5x - x - 4-8
or, 0= 4x - 12
Answer:
A -6 < x ≤ -3
Step-by-step explanation:
21 ≤ - 3(x - 4) < 30
Divide all parts by -3. Remember that flips the inequalities
21/-3 ≥ - 3/-3 (x - 4) > 30/-3
-7 ≥ (x - 4) > -10
Add 4 to all sides
-7+4 ≥ x - 4+4 > -10+4
-3 ≥ x > -6
Rearranging the order
-6 < x ≤ -3
Answer:
x = 3, y = 7
or (3,7)
Step-by-step explanation:
We are given the system of equations below:

We are required to solve the system by substitution method. What we have to do is to isolate either x-term or y-term so we can use the method. I will be isolating y-term because it is faster due to having 1 as a coefficient.
By isolating y-term, just pick one of the given equations to isolate. No need to isolate the whole system. (I will be isolating y-term of the first equation.)

Then we substitute y = 2x+1 in the second equation.

Use the distribution property.

Isolate x-term to solve the equation.

Since we are solving a system of equations. We have to solve for both x-value and y-value to complete. We have already found x-value, but nor y-value yet. Therefore, our next step is to substitute the value of x that we solved in any given equations. It's recommended to substitute in an equation that doesn't have high coefficient value. So I will be substituting x = 3 in the first equation.

Isolate and solve for y-term.

Since we substitute x = 3 and get y = 7. We can write in ordered pairs as (3,7)
Hence, the solution is (3,7)