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tensa zangetsu [6.8K]
3 years ago
15

A 12,000-lb killer whale might eat as much as 14,000 lb of fish per month (assume a 30-day month). If the average weight of a ce

rtain type of fish is 3.4 oz, estimate how many of these fish a killer whale would eat in a day.† (Round your answer to the nearest whole number.)
Mathematics
1 answer:
brilliants [131]3 years ago
8 0

Answer:

2196 fish

Step-by-step explanation:

Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb

Weight of the fish that killer whale might eat in a day = \frac{14000}{30} = \frac{1400}{3} lb.

Average weight of the fish that killer whale eats = 3.4 oz

Since,

1 pound(lb) = 16 ounces(oz)

So,

Weight of the fish that killer whale might eat in a day in ounces(oz) = \frac{1400}{3} \times 16=\frac{22400}{3} oz

Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.

So, the number of fish that killer whale would eat = \frac{22400}{3} \div 3.4 = 2196 fish

Thus, the killer whale needs to eat 2196 fish.

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Mr. Jones bought a cloth of length 3890 cm. How much is the length in m and cm?
devlian [24]

Answer:

38m and 90cm

1m = 100cm

3890cm = 38m and 90cm

Step-by-step explanation:

1m = 100cm

3890cm = 38m and 90cm

3 0
2 years ago
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- 7th Grade Work -<br><br> I rlly need help ; - ;
Tanya [424]

Answer:

The length would be 1.5x + 5.

Step-by-step explanation:

So first with this, note that 2 length + 2 height gives the perimeter of the rectangle.

Given this:

2(1/2x + 4) + 2(?) = 4x+18

x+8 + 2(?) = 4x+18

2(?) = 3x+10

? = 1.5x+5

1.5x + 5 = 1.5x + 5

The length would be 1.5x + 5.

To double check, by plugging in 1.5x + 5 back into the equation for the perimeter, you will get the same perimeter:

2(1.5x + 5) + 2(1/2x+4) = P

3x+10 + x+8 = P

4x + 18 = P

8 0
3 years ago
2/5 times ( -10)=?<br> ?=
Rudiy27

\frac{2}{5}  \times ( - 10)

2 \times  - 2

- 4

6 0
3 years ago
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Determine the domain and range of the function f(x)= 3x+2. Also, state the intervals where the function f(x)= 3x+ 2 is increasin
aev [14]

Answer:

Increasing on it's domain (-\infty,\infty) because the slope is positive.

The domain and range are both all real numbers, also known as

(-\infty,\infty).

Step-by-step explanation:

All domain really means is what numbers can you plug in and you get number back from your function.

I should be able to plug in any number into 3x+2 and result in a number. There are no restrictions for x on 3x+2.

The domain is all real numbers.

In interval notation that is (-\infty,\infty).

Now the range is the set of numbers that get hit by y=3x+2.

Well y=3x+2 is a linear function that is increasing.  I know it is increasing because the slope is positive 3. I wrote out the positive part because that is the item you focus on in a linear equation to determine if is increasing or decreasing.

If slope is positive, then the line is increasing.

If slope is negative, then the line is decreasing.

So y=3x+2 hits all values of y because it is increasing forever.  The range is all real numbers. In interval notation that is (-\infty,\infty).

3 0
3 years ago
Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

Answer:

0

Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

So we integrate r from 0 to 9 and θ from 0 to 2π.

∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ

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= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ

= 8[6561/4]∫(cosθsinθ)dθ

= 13122∫(cosθsinθ)dθ

Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2

Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

= 13122/2[-cos2θ]/2 from 0 to 2π

13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]

= -13122/4[cos4π - cos(0)]

= -13122/4[1 - 1]

= -13122/4 × 0

= 0

5 0
3 years ago
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