I think it’s C but I’m not too sure
Volume of the cone is 100 in³
Step-by-step explanation:
- Step 1: Volume of a cone = 1/3 πr²h. Find volume of the cone where r = 3 inches and h = 9 inches.
Volume = 1/3 × 3.14 × 3² × 9
= 84.78 in³ ≈ 100 in³ (rounding off to nearest hundredth)
Answer:
The farmer should plant 14 additional trees, for maximum yield.
Step-by-step explanation:
Given



So, we have:


Required
The additional trees to be planted for maximum yield
The function is:


Open bracket



Rewrite as:

Differentiate

Equate
to 0 and solve for x to get the maximum of x


Divide by -4

The farmer should plant 14 additional trees, for maximum yield.
Answer:
no
Step-by-step explanation:
Cost less salvage value = 970,000 - 4500 = 965,500
Capacity of machine = 1,000,000 units.
units consumed at the end of second year = 200,000 + 300,000 = 500,000 units.
Capacity remaining = 1,000,000 - 500,000 = 500,000 units
Book value at end of second year = (500,000/1,000,000)*965,500 + 4500
= $487,250