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Murljashka [212]
3 years ago
8

12y+8=2x Solve for x and y

Mathematics
2 answers:
KiRa [710]3 years ago
7 0
I’m learning this right now so first you will subtract 8 on both sides of the equation. Then, rewrite it as 12y=2x-8. Next you will divide by 12 to each number when you are done then rewrite it as y=1/6x-2/3. Then for x you will divide by 2 on both sides and it would be x=6y+4. Well, that’s how I’m learning it I don’t know if that’s the same way you are learning it. But there you go
Artemon [7]3 years ago
3 0

12y+8=2x\qquad\text{subtract 8 from both sides}\\\\12y=2x-8\qquad\text{divide both sides by 12}\\\\y=\dfrac{2}{12}x-\dfrac{8}{12}\\\\\boxed{y=\dfrac{1}{6}x-\dfrac{2}{3}}\\\\2x=12y+8\qquad\text{divide both sides by 2}\\\\\boxed{x=6y+4}

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8.96 g/cm2

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3 years ago
Please help me with this question
Alenkasestr [34]

Answer:

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2 years ago
A.) which of these expressions is equivalent to 4 x x
Law Incorporation [45]

Answer:

a) The correct option is C: 4x

b) The correct option is B: 2x

Step-by-step explanation:

a) Usually when we have a real number multiplying a variable, we do not need to write the multiplication symbol.

So instead of writing:

4×x

We can write:

4x

And this will be equivalent.

Then in this case the correct option is C.

b) We know that if we have the multiplication of A by n, this will be equivalent to add A n times.

Then if we have the sum of A, for example, 4 times, we have:

A + A + A + A

And this can be written as 4*A

In this case, we have the expression x + x.

So we are adding x two times, then this can be written as: 2*x, or, as we said earlier, this also can be written as 2x.

Then the correct option is option B.

8 0
2 years ago
Help me? idk the answer :P
Alexus [3.1K]
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
\\\\
-------------------------------\\\\


\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\
-------------------------------\\\\
\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4

\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
-------------------------------\\\\
\textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8}
\\\\\\
\cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}

\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9
7 0
2 years ago
A basketball player has a 50% chance of making each free throw. What is the
Ne4ueva [31]

Answer:

20.508%

Step-by-step explanation:

1/2 chance for one free throw.

1/2*4/10=4/20=1/5

Therefore, 20.508%

8 0
3 years ago
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