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Bingel [31]
3 years ago
11

Tell whether the relationship is a proportional relationship. if so, give the constant of proportionality

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
5 0
Proportional because it's a straight line if you follow the graph points and it goes by 5
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Answer:

its 11/6

Step-by-step explanation:

GCD of 11 and 6 is 1

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11 ÷ 1

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Reduced fraction:  

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How do i solve for x and what is the answer
kiruha [24]

Answer:

(4+8)(4) = (x) 3

Step-by-step explanation:

The picture shows two secants intersecting at a point outside the circle.  A beautiful pattern for this is:  along each secant, the product (multiply) the <em>entire</em> secant by the <em>outside</em> part is the same.

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3 years ago
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vovangra [49]

<em>Here's</em><em> </em><em>my</em><em> </em><em>working</em><em> </em><em>for</em><em> </em><em>1</em><em>)</em><em> </em><em>You</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>exterior</em><em> </em><em>angle</em><em>,</em><em> </em><em>then</em><em> </em><em>divide</em><em> </em><em>by</em><em> </em><em>360</em><em> </em><em>to</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>sides</em><em>:</em>

<em>Applying</em><em> </em><em>these</em><em> </em><em>steps</em><em> </em><em>:</em><em> </em>

180 (Interior Angles) - 162 = 18 (Exterior angle)

360 ÷ 18 is<em> </em><em>20</em><em> </em><em>sides</em><em> </em>

<em>For</em><em> </em><em>2</em><em>)</em>

<em>Its</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>method</em><em>,</em><em> </em><em>so</em><em> </em><em>apply</em><em> </em><em>the</em><em> </em><em>steps</em><em>:</em>

<em>180</em><em> </em><em>-</em><em> </em><em>175</em><em> </em><em>=</em><em> </em><em>5</em>

<em>360</em><em> </em><em>÷</em><em> </em><em>5</em><em> </em><em>=</em><em> </em><em>72</em><em> </em><em>sides</em><em> </em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>!</em><em> </em><em>:</em><em>)</em><em> </em>

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