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jeka57 [31]
3 years ago
5

water molecules are postivtivley charged on one end and negitivley charged on the other. what does this property allow water to

do
Chemistry
1 answer:
Inga [223]3 years ago
5 0
This property allows water to be very good at separating ionic solids because of the polar moment which attaches to the positive and negative molecules, respectively.
<u>Remember</u>: water is the most polar solvent.
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Dima020 [189]
The earth wouldn’t have an atmosphere
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What is the constant parameters of pressure and volume? The relationship between the two? Are they directly proportional or inve
OverLord2011 [107]
Now I'm just going to assume you mean Charles law. So when working with gases, there are 4 properties: pressure, volume, temp, and quantity. The simple gas laws deal with 2, while leaving the other 2 constant. If Charles' Law changes temp and volume, what 2 stay constant? Pressure and quantity
6 0
3 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
Using the following equation for the combustion of octane calculate the heat associated with the formation of 100.0 g of carbon
natali 33 [55]

Answer:

The right solution is "-602.69 KJ heat".

Explanation:

According to the question,

The 100.0 g of carbon dioxide:

= \frac{100.0 \ g}{114.33\  g/mole}

= 0.8747 \ moles

We know that 16 moles of CO_2 formation associates with -11018 kJ of heat, then

0.8747 moles CO_2 formation associates with,

= -\frac{0.8747}{16}\times 11018 \ KJ \ of \ heat

= -0.0547\times 11018

= -602.69 \ KJ \ heat

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3 years ago
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aleksklad [387]
S8 + 12O2 yields 8SO3
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