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Rus_ich [418]
4 years ago
6

What is the percent of iron and oxygen in iron(III) oxide?

Chemistry
1 answer:
ch4aika [34]4 years ago
6 0

Answer:

69.94% iron by mass.

Explanation:

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A chemist is studying small organic compounds for their potential use as an antifreeze. When 0.243 g of a compound is dissolved
harina [27]

Molar mass = 144.2 g/mol.

<h3>Calculate Molar mass.</h3>

Formula to solve this: ΔT = Kf . m

ΔT → Freezing point of pure solvent - Freezing point of solution

0°C - (-1.94°C) = 1.86 °C/m . m

1.94°C / 1.86 m/°C = m →  1.04 m

1.04 are the moles of solute in 1kg of solvent → molality (mol/kg)

Let's convert the mass of our solvent in kg to determine the moles.

80 g . 1kg / 1000 g = 0.08 kg

Molality . kg of solvent → Solute moles

1.04 mol/kg . 0.080 kg = 0.0832 moles

These are the moles of 12 g of solute. To find the molar mass → g/mol

12 g / 0.0832 mol = 144.2 g/mol

To learn more about Molar mass from the given link:

brainly.com/question/14787860

#SPJ4

4 0
1 year ago
What is test for ions?​
fomenos
It is possible to use a flame test to detect the presence of an alkali metal ion. A cleaned, moistened flame test wire is dipped into a solid sample of the compound. It is then put into the edge of a blue Bunsen flame. The flame colour produced indicates which alkali metal ion is present in the compound.






Hope it works plz mark me as brainliest
7 0
3 years ago
Read 2 more answers
HURRY! 10 POINTS!!
frosja888 [35]

Answer:

Weak bonds require less energy to form than strong bonds

Explanation:

According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.

As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.

Bond energy is defined as the amount of energy required to break the bond. If a bond is weak, it would require a low amount of energy to break it. This is also true for energy of formation, as it's the same process taking place in the opposite direction.

6 0
4 years ago
Which elements does it take to spell "nerds" using the chemical symbols on the Periodic Table of Elements?
Veseljchak [2.6K]
If we looks at the elements and the periodic table . A is correct because Nitrogen is N , Ensteinium is E, Radon is RN, and lastly S is sulfer.

I hope this helps you! :)
7 0
3 years ago
Between Lab Period 1 and Lab Period 2, design a separation scheme for all 4 cations. Use the results of your preliminary tests a
fiasKO [112]

Answer:

                    SEPARATION SCHEME FOR  CATIONS

GIVEN  CATIONS : Ag^{+} \ ,  Fe^{3+} , Cu^{2+}, Ni^{2+}

     

    Step 1:   Add 6mol/dm^3 of HCl to the mixture solution

    Result : This would cause a precipitate of AgCl to be formed

    Reaction :  Ag^{+} _{(aq)} + Cl^{-} _{(aq)}  ---------> AgCl(ppt)

    Step 2 : Next is to remove the precipitate and add H_2S to the remaining          

                 solution in the presence of 0.2 \ mol/dm^3 of HCl

     Result : This would cause a precipitate of CuS to be formed

     Reaction :  Cu^{2+}_{(aq)} + S^{2-}_{(aq)} ------> Cu_2S(ppt)

 

     Step 3: Next remove the precipitate then add 6 \ mol/dm^3 of aqueous      

                 NH_3 (NH_3 \cdot H_2 O) , process the solution in a centrifuge,when the  

                 process  is done then sort out the  precipitate from the  solution

                 Now this precipitate is   Fe(OH)_3 and the remaining solution

                contains  (Ni (NH_3)_6)

                 Next take out the precipitate to a different beaker and add HCl

                to it   this will dissolve it, then add a drop of NH_4SCN this will

                form  a precipitate  Fe(SCN)_{6}^{3-} which will have the color of

                 blood  indicating the presence of Fe^{3+}

             

   Reaction :   F^{3+}_{(aq)} + 30H^-_{(aq)} --------->Fe(OH)_3_{(aq)}

                        Fe (OH)_{(s)} _3  + 3H^{+}_{aq} -------> Fe^{3+}_{aq} + 3H_2O_{(l)}

                         Fe^{3+} + 6SCN^{-} -----> Fe(SCN)_6 ^{3-}

                      Now the remaining mixture contains Ni^{2+}

     

       

Explanation:

6 0
3 years ago
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