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Mama L [17]
4 years ago
7

Triangle L M Q is cut by perpendicular bisector L N. Angle N L Q is 32 degrees and angle L M N is 58 degrees.

Mathematics
1 answer:
Serga [27]4 years ago
8 0

Answer:

Yes

Step-by-step explanation:

ΔMNL ≅ ΔQNL  by ASA or AAS

by ASA

Proof:

∠ LNM = ∠LNQ    =90

LN = LN   {Common}

∠MLN = ∠QLN     {LN bisects ∠ L}

By AAS

∠Q + ∠QLN + ∠LNQ = 180  {Angle sum property of triangle}

∠Q + 32 + 90 = 180

∠Q  + 122 = 180

∠Q = 180 -122 =

∠Q = 58

∠Q = ∠M

∠MNL =∠QNL = 90

LN = LN {common side}

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5 0
3 years ago
Given: KLMN is a trapezoid m∠K = 90°, m∠N = 45° LK = LM = 10 Find: KN, Area of KLMN
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Let KLMN be a trapezoid (see added picture). From the point M put down the trapezoid height MP, then quadrilateral KLMP is square and KP=MP=10.
A triangle MPN is right and <span>isosceles, because
</span>m∠N=45^{0}, m∠P=90^{0}, so m∠M=180^{0}-45^{0}-90^{0}=45^{0}.Then PN=MP=10.
The ttapezoid side KN consists of two parts KP and PN, each of them is equal to 10, then KN=20 units.
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