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notka56 [123]
2 years ago
14

Will give brainliest. How long is this side?

Mathematics
2 answers:
Maurinko [17]2 years ago
7 0
Your answer is 35 :) 

Have a great day!!

If I'm correct give me 5 stars and brainliest. 
Olegator [25]2 years ago
5 0
35 is the answer.


Have questions? let me know (:


Good Luck! 
You might be interested in
Express the function y(t)= 4 sin 2πt + 15 cos 2πt in terms of (a) a sine term only. (b) Determine the amplitude, the period, the
Bond [772]

Answer:

See the step by step solution

Step-by-step explanation:

Consider a more general case of the form a\sin(x)+b\cos(x). We want to express it as a sine term only by using the following formula \sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)

The trick  consists on find a number \beta \in [0,2\pi] such that \cos(\beta) = a, \sin(\beta)=b . But, note that since \cos^2(\beta)+\sen^2(\beta)=1 it is most likely that a^2+b^2neq 1. Then, we will use the following equations:

\cos(\beta) =\frac{a}{\sqrt[]{a^2+b^2}=A,\sin(\beta) =\frac{b}{\sqrt[]{a^2+b^2}=B

Then, problem turns out to be

a\sin(x)+b\cos(x)= \sqrt[]{a^2+b^2}(A\sin(x)+B\cos(x)) =\sqrt[]{a^2+b^2}(\sin(x)\cos(\beta)+\sin(\beta)\cos(x))=\sqrt[]{a^2+b^2}\sin(x+\beta),

where \beta = \tan^{-1}(\frac{B}{A})= \tan^{-1}(\frac{b}{a}). So, note that the frequency is the same. Then, a) Taking a=4 and b= 15 we have that 4 sin 2πt + 15 cos 2πt= [tex]\sqrt[]{15^2+4^2}\sin(2\pi t + \tan^{-1}\frac{15}{4})

b) The amplitude is \sqrt[]{15^2+4^2} = \sqrt[]{241}. Since 2\pi rad/s = 1 Hz the frequency is 1 Hz. The period is given by \frac{2\pi}{2\pi} = 1.

c) The function's graph is attached

7 0
3 years ago
Read 2 more answers
What is the answer to, one half of 9?
GREYUIT [131]
Answer:

4.5

Step-by-step explanation:

One half of 9 = 9/2 = 4.5
7 0
2 years ago
The triangles are similar. If QR = 9, QP = 6, and TU = 19, find TS. Round to the nearest tenth.
sineoko [7]
Answer=12.6

QR=9
QP=6
TU=19
TS=?

The triangles are similar, so the following equation can be made

   9         6
____=____
  19        x        

Cross multiply
9x=114
divide both sides by 9
x=12.6 (with the 6 repeating) or 12 2/3

TS=12.6
3 0
3 years ago
Read 2 more answers
For second answer how do you get it plz urgent plz
inna [77]

Step-by-step explanation:

Complete question is attached.

Answer:

a) ED = 6.5 cm

b) BE = 14.4 cm

Step-by-step explanation:

From the triangle, we are given the following dimensions:

AB = 20 cm

BC = 5 cm

CD = 18 cm

AE = 26 cm

We are asked to find length of sides ED and BE.

a) Find length of ED.

From the triangle Let's use the equation:

\frac{AB}{BC} = \frac{AE}{ED}BCAB=EDAE

Cross multiplying, we have:

AB * ED = AE * BC

From this equation, let's make ED subject of the formula.

ED = \frac{AE * BC}{AB}ED=ABAE∗BC

Let's substitute figures,

ED = \frac{26 * 5}{20}ED=2026∗5

ED = \frac{130}{20} = 6.5ED=20130=6.5

Therefore, length of ED is 6.5 cm.

b) To find length of BE, let's use the equation:

\frac{AB}{AC} = \frac{BE}{CD}ACAB=CDBE

Cross multiplying, we have:

AB * CD = AC * BE

Let's make BE subject of the formula,

BE = \frac{AB * CD}{AC}BE=ACAB∗CD

From the triangle, length AC = AB + BC.

AC = 20 + 5 = 25

Substituting figures, we have:

BE = \frac{20 * 18}{25}BE=2520∗18

BE = \frac{360}{25} = 14.4BE=25360=14.4

Therefore, length Of BE is 14.4cm

I JUST SO THAT IN INTERNET:)

4 0
3 years ago
Exact = 50 Approximate = 45
Nikitich [7]

Answer:

Approximate of error = 11.11 % (Approx.)

Step-by-step explanation:

Given:

Exact value = 50

Approximate value = 45

Find:

Approximate of error

Computation:

Approximate of error = [(Exact value - Approximate value)/Approximate value]100

Approximate of error = [(50 - 45)/45]100

Approximate of error = [(5)/45]100

Approximate of error = [0.11111]100

Approximate of error = 11.11 % (Approx.)

3 0
3 years ago
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