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faltersainse [42]
4 years ago
15

Given that 3x + y = 0 and 2x - y = 5, find the value of y.​

Mathematics
1 answer:
professor190 [17]4 years ago
4 0

Answer:

<em>3x</em><em> </em><em>+</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>0</em>

<em>x</em><em> </em><em>=</em><em> </em><em>-</em><em>y</em><em>/</em><em>3</em>

<em>Now</em><em>,</em><em> </em>

<em>2x</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>5</em>

<em>2</em><em> </em><em>(</em><em>-</em><em>y</em><em>/</em><em>3</em><em>)</em><em> </em><em>-</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>5</em>

<em>(</em><em>-</em><em>2y</em><em> </em><em>-</em><em> </em><em>3y</em><em>)</em><em>/</em><em>3</em><em> </em><em>=</em><em> </em><em>5</em>

<em>-</em><em>5y</em><em>/</em><em>3</em><em> </em><em>=</em><em>5</em>

<u><em>y</em><em>=</em><em>-</em><em>3</em></u>

<em>#</em><em>$</em><em>#HOPE</em><em> </em><em>YOU</em><em> </em><em>UNDERSTAND</em><em> </em><em>#</em><em>$</em><em>#</em>

<em>#</em><em>$</em><em>¥</em><em> </em><em>THANK</em><em> </em><em>YOU</em><em> </em><em> ¥</em><em>$</em><em>#</em>

<em>❤</em><em> </em><em>☺</em><em> </em><em>☺</em><em> </em><em>☺</em><em> </em><em /><em> </em><em>☺</em><em> </em><em>☺</em><em> </em><em>☺</em><em> </em><em>❤</em><em> </em>

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How far is a chord of length 8 cm from the centre of a circle of radius 5 cm
ivann1987 [24]
  • Answer:

<em>OB = 3 cm</em>

  • Step-by-step explanation:

<em>AO = radius = 5 cm</em>

<em>AB = 8cm/2 = 4 cm</em>

<em>Pythagora</em>

<em>OB² = AO² - AB²</em>

<em>= (5cm)² - (4cm)²</em>

<em>= 25cm² - 16cm²</em>

<em>= 9 cm²</em>

<em>OB = √9cm²</em>

<em>= 3 cm</em>

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cited from web2.0calc

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3 years ago
Find the value of x. Enter only the number.
Sophie [7]

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Of the following, which is the solution to 2x2 + 3x = −5? (6 points) Select one: a. the quantity negative three plus or minus i
jeka94

"2x2 + 3x = −5" should be re-written as 2x^2 + 3x +5 = 0. This is a quadratic equation with a=2, b=3 and c=5. Thus, the roots are:

-3 plus or minus √(9-4[2][5])

x = ---------------------------------------------

4

or:

-3 plus or minus √(-31)

x = ----------------------------------

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or:

-3 plus or minus i*√31

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4 0
4 years ago
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