Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
The answer is B (There is evidence that a Type BBB orange typically weighs more than a Type AAA orange.) this is right on edulastic
Answer:
B. 4m
Step-by-step explanation:
What you do is you just take the 8 and put it into the m.
m-8, 8-8=0 so A isn't your answer.
4m, 4(8)=32 so B is your answer.
B. 4m is your answer.
Answer:
131
Step-by-step explanation:
Using proportion,
If Out of 550 calculators = 6 are defective,
Then out of 12000 calculators = ? are defective
= 21.8 * 6
= 130.8 ≈ 131
∴ Approximately 131 calculators are defective
