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denis23 [38]
2 years ago
7

Simplify -2 1/9 -(-4 1/3)

Mathematics
2 answers:
ololo11 [35]2 years ago
8 0
The answer to this is 20/9
vesna_86 [32]2 years ago
3 0

Answer:

\frac{20}{9} or 2 \frac{2}{9}

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Given: A ABC<br> The measure of measure of
shepuryov [24]

Answer:

∠A = 90  

∠B = 30

∠C = 60

Step-by-step explanation:

Let ∠B = x

∠A = 3x

∠C = x + 30

Angle sum property of triangle: Sum of three angles of triangle is 180

x + 3x + x + 30 = 180   {Combine like terms}

         5x  + 30 = 180

                    5x = 180 - 30

                   5x = 150

                     x = 130/5

x = 30

∠A = 3*30 = 90

∠C = 30 + 30 = 60

5 0
3 years ago
What is 2 2/3×3 1/4 as a fraction form
fgiga [73]
The fraction form is 26/3 or 8 2/3
8 0
2 years ago
7n+2 = 4n+17 solve the equation
lions [1.4K]

Answer:

n = -5

Step-by-step explanation:

Solve for n:

n + 2 = 4 n + 17

Hint: | Move terms with n to the left hand side.

Subtract 4 n from both sides:

(n - 4 n) + 2 = (4 n - 4 n) + 17

Hint: | Combine like terms in n - 4 n.

n - 4 n = -3 n:

-3 n + 2 = (4 n - 4 n) + 17

Hint: | Look for the difference of two identical terms.

4 n - 4 n = 0:

2 - 3 n = 17

Hint: | Isolate terms with n to the left hand side.

Subtract 2 from both sides:

(2 - 2) - 3 n = 17 - 2

Hint: | Look for the difference of two identical terms.

2 - 2 = 0:

-3 n = 17 - 2

Hint: | Evaluate 17 - 2.

17 - 2 = 15:

-3 n = 15

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of -3 n = 15 by -3:

(-3 n)/(-3) = 15/(-3)

Hint: | Any nonzero number divided by itself is one.

(-3)/(-3) = 1:

n = 15/(-3)

Hint: | Reduce 15/(-3) to lowest terms. Start by finding the GCD of 15 and -3.

The gcd of 15 and -3 is 3, so 15/(-3) = (3×5)/(3 (-1)) = 3/3×5/(-1) = 5/(-1):

n = 5/(-1)

Hint: | Simplify the sign of 5/(-1).

Multiply numerator and denominator of 5/(-1) by -1:

Answer: n = -5

5 0
2 years ago
What is 40 1/3 divided by 50
solong [7]
121/150 or 0.0806. The 6 is repeating itself.
8 0
3 years ago
Read 2 more answers
The figure shows a circle inscribed in a triangle. To construct the inscribed circle, angle bisectors were first constructed at
klemol [59]

Answer:

Segments perpendicular to the sides of the triangle through the intersection of the angle bisectors were constructed.

Step-by-step explanation:

The above choice represents a bit of excess work. Actually, only one such perpendicular line segment needs to be constructed in order to determine the radius of the inscribed circle.

Once you know the center and radius, you can construct the inscribed circle.

7 0
3 years ago
Read 2 more answers
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