So our equation currently is ⇒ 
<u>Let's first move all the constant to one side and group 'like variables' together</u>:
<u>Now lets complete the square of both equations</u>
<u><em>Now we know the circle's general equation format is</em></u>:
⇒
- (h, k) ⇒ coordinate of the center of the circle
- r ⇒ length of radius of circle
<u>Thus the radius of the circle is 7</u>
<u></u>
Hope that helps!
It’s B because m is smaller than cm
Answer:
11/24 as a fraction but a decimal 0.4583 ( the three is recurring)
There are two of them.
I don't know a mechanical way to 'solve' for them.
One can be found by trial and error:
x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
<em>x=4</em> . . . . . 2^4 = <em><u>16</u></em> . . . . 4(4) = <em><u>16</u></em> . . . . Yes ! That works ! yay !
For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.
The point is near, but not exactly, <em>x = 0.30990693...
</em>If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks.<em> </em> If anybody out there has it, I'm
waiting with all ears.<em>
</em>
Answer:
x = 30
Step-by-step explanation:
x + 2x + 3x = 180
<u>6x</u> = <u>180</u>
6 6
x = 30
