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2 years ago

Simplify -2 1/9 -(-4 1/3)

Mathematics

2 answers:

ololo11 [35]2 years ago

8 0

The answer to this is 20/9

vesna_86 [32]2 years ago

3 0

Answer:

$\frac{20}{9}$ or $2 \frac{2}{9}$

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Write the missing numbers to show equivalent fractions for some common numbers used as benchmarks

erastovalidia [21]

Answer:

Step-by-step explanation:

gew;iF:hb

3 0

3 years ago

Read 2 more answers

1. The backdrop of the altar in a church is triangular in shape. It has a base of 10.5 meters

FrozenT [24]

Answer:

Area of triangle backdrop:

A = 1/2bh = 1/2(10.5)(8.5) = 44.63 m²

Area of the cloth:

A = 4.5*4 = 18 m²

Uncovered area:

44.63 - 18 = 26.63 m²

Choice A

Area of the cut piece:

A = πr² = 3.14*7.6² = 181.37 cm²

Area of the square piece:

A= a² = 34² = 1156 cm²

Remaining piece is:

1156 - 181.37 = 974.63 cm²

Choice B

8 0

2 years ago

Determine whether the given measures can be the lengths of the sides of a triangle write yes or no

ohaa [14]

NO.,the given measures can not be the lengths of the sides of a triangle

Step-by-step explanation

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

so, Find the range for the measure of the third side of a triangle given the measures of two sides.

here given measures are 2,2,6

2+2 = 4 which is less than the third side 6

= 4 < 6

This not at all a triangle.

Hence, the given measures can not be the lengths of the sides of a triangle

3 0

3 years ago

The radius of a circle is 9.7m. find the circumference to the nearest tenth

ludmilkaskok [199]

Answer:

61.0

Step-by-step explanation:

Formula for Circle

2πr

π = 3.14

r = Radius

5 0

3 years ago

A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019

kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

$6\5=\frac{6}{100}=0.06$

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

$y=14,000*(1-0.06)^x$

$y=14,000*(0.94)^x$

Let us find x by subtracting 2010 from 2019.

$x=2019-2010=9$

Upon substituting x=9 in our function we will get,

$y=14,000*(0.94)^9$

$y=14,000*0.5729948022286167$

$y=8021.927\approx 8022$

Therefore, the population of fish in 2019 will be 8022.

6 0

3 years ago