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likoan [24]
3 years ago
13

Pls help I’ll brainlest x to the power 2=0.09

Mathematics
1 answer:
Vesnalui [34]3 years ago
8 0

Answer:

0.3 & -0.3

Step-by-step explanation:

x^2=0.09

take the square root of both sides to get 0.3 & -0.3

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Please answer this ASAP
k0ka [10]

Answer:

c: x=2

Step-by-step explanation:

5x-3= 13-3x

   +3      +3

5x=16-3x

+3      +3

8x=16

divide all of it by 8 and thats how you get your answer

5 0
2 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
Please help on this math question
Katarina [22]
First and last ones
The " = [number] " at the end of an equation for a circle is the radius squared
So if the diameter is 12, then the radius is 6, and 36 is 6 squared
Also as long as the x term doesn't have an integer affecting it (like -3 or +5) then it'll stay on the y axis.
4 0
3 years ago
Marianne, Arlene, Tyler, and I worked together to complete a group project. Marianne completed 1/5 of the project. Arlene comple
Nookie1986 [14]
Marianne completed 2/10 and Arlene 3/10 so that’s 5/10 which means you and Tyler did 5/10 if you divide that by 2 it’s 5/20 I think but I don’t really understand as the possible answers aren’t fractions? Hopefully that’s right haha
3 0
4 years ago
Select all ratios equivalent to 4:16.<br> 3:12<br> 6:48<br> 5:4
PSYCHO15rus [73]

Answer

Step-by-step explanation:

neither

brainlest

6 0
3 years ago
Read 2 more answers
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