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kozerog [31]
3 years ago
15

Find the Volume of the square pyramid of the area of the base is 48cm and the height is 8cm.

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

A

Step-by-step explanation:

too much explaining but trust me

Katen [24]3 years ago
7 0

Answer:128cm^3

Step-by-step explanation:

Base area=48cm^2

Height=8cm

Volume=1/3 x base area x height

Volume=1/3 x 48 x 8

Volume=(1x48x8)/3

Volume=384/3

Volume =128cm^3

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Answer:

I think you may have forgot to put in the rest of the question mate

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Triss [41]

Answer:

He can cut 6 sections this length.

Step-by-step explanation:

he has

7(12) = 84 inches of rope.

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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
What can you do when the unit prices for two comparable items are listed using different units of measure?
Over [174]
When you have two unit prices for two comparable items, you have to convert one of the prices to the other one.
3 0
3 years ago
Read 2 more answers
Help me pls!
mafiozo [28]

Answer:

  • 6 ≤ x ≤ 12

Step-by-step explanation:

<u>Area formula</u>

  • A = lw

<u>Applied to the given rectangle, we have</u>

  • A = 1.5*4x = 6x

<u>Since 36 ≤ A ≤ 72, substituting A</u>

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It is viable.

8 0
2 years ago
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