Hello!
I don't exactly understand your question. If you mean to be asking whether or not 1002 is geater than 100, it is.
If you mean to be asking to add it: 102 + 900 + 100 = 1102
Answer:
![-7y](https://tex.z-dn.net/?f=-7y)
Step-by-step explanation:
Our equation is:
![\left(1x-5y\right)-1\left(x+2y\right)](https://tex.z-dn.net/?f=%5Cleft%281x-5y%5Cright%29-1%5Cleft%28x%2B2y%5Cright%29)
First we dritribute
Now we have, ![x-5y-x-2y](https://tex.z-dn.net/?f=x-5y-x-2y)
light terms
and we get ![-7y](https://tex.z-dn.net/?f=-7y)
Tell me if there is still confusion and i'll go steo by step.
We have two equations
One to for the total number of units, to distinct them from 1 bedroom units or 2 bedroom units
x- one bedroom units
y- two bedroom units
x+y= 100
495x+600y= 55,275
We can try to plug in these values for y since it’s asks “how many two bedroom apartments are there” and see if it works out
495x+600(45)= 55,275
495x+27000=55275
-27000 -27000
495x= 28275
/495 /495
x=57.12
There can’t be 57.12 units so A is wrong
495x+600(55)= 55,275
495x+ 33000= 55275
-33000 -33000
495x =22275
/495 /495
x=45
This could work so B is the answer , you could go ahead and try C and B but most likely the answer is B
Answer:
Using trigonometric ratio:
![\sec \theta = \frac{1}{\cos \theta}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7B1%7D%7B%5Ccos%20%5Ctheta%7D)
![\tan \theta = \frac{\sin \theta}{\cos \theta}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D)
From the given statement:
and sin < 0
⇒
lies in the 3rd quadrant.
then;
![\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D%20%5Cfrac%7B1%7D%7B-%5Cfrac%7B4%7D%7B5%7D%7D%20%3D%20-%5Cfrac%7B5%7D%7B4%7D)
Using trigonometry identities:
Substitute the given values we have;
![\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%20%3D%20%5Cpm%5Csqrt%7B1-%28%5Cfrac%7B-4%7D%7B5%7D%29%5E2%20%7D%20%3D%5Cpm%5Csqrt%7B1-%5Cfrac%7B16%7D%7B25%7D%7D%20%3D%5Cpm%5Csqrt%7B%5Cfrac%7B25-16%7D%7B25%7D%7D%20%3D%5Cpm%20%5Csqrt%7B%5Cfrac%7B9%7D%7B25%7D%20%7D%20%3D%20%5Cpm%5Cfrac%7B3%7D%7B5%7D)
Since, sin < 0
⇒![\sin \theta = -\frac{3}{5}](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%20%3D%20-%5Cfrac%7B3%7D%7B5%7D)
now, find
:
![\tan \theta = \frac{\sin \theta}{\cos \theta}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%20%5Cfrac%7B%5Csin%20%5Ctheta%7D%7B%5Ccos%20%5Ctheta%7D)
Substitute the given values we have;
![\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%20%3D%20%5Cfrac%7B-%5Cfrac%7B3%7D%7B5%7D%20%7D%7B-%5Cfrac%7B4%7D%7B5%7D%20%7D%20%3D%20%5Cfrac%7B3%7D%7B5%7D%5Ctimes%20%5Cfrac%7B5%7D%7B4%7D%20%3D%20%5Cfrac%7B3%7D%7B4%7D)
Therefore, the exact value of:
(a)
![\sec \theta =-\frac{5}{4}](https://tex.z-dn.net/?f=%5Csec%20%5Ctheta%20%3D-%5Cfrac%7B5%7D%7B4%7D)
(b)
![\tan \theta= \frac{3}{4}](https://tex.z-dn.net/?f=%5Ctan%20%5Ctheta%3D%20%5Cfrac%7B3%7D%7B4%7D)