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4 years ago

A package is shaped like a right rectangular prism. Use the dimensions shown to find the total surface area of this package

Mathematics

1 answer:

Slav-nsk [51]4 years ago

5 0

Answer:

22 ft²

Step-by-step explanation:

2[ 2×1 + 3×1 + 3×2 ]

2(2 + 3 + 6)

2(11)

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when the whole is the same why does it take 4 copies of one tenth to equal 2 copies of one fifth draw a model to support your an

bonufazy [111]

Well 4 copies of one tenth will equal 4 tenths. so when u simplify 4 over ten (4/10 )and divide the top and bottom by the common factor which is 2 then you will get 2 fifths because 4 divided by 2 is 2 and 10 divided by 2 is 5.

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4 years ago

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Firdavs [7]

The 1st one is 6, 2nd: 2.

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3 years ago

2 and a half plus 2 and a half

Wittaler [7]

Answer:

Step-by-step explanation:

Using fractions:

$2\frac{1}{2}$ = $\frac{5}{2}$

$\frac{5}{2}$ + $\frac{5}{2}$ = $\frac{10}{2}$

$\frac{10}{2}$ = 5

Using decimals:

$2\frac{1}{2}$ = 2.5

2.5 + 2.5 = 5

7 0

3 years ago

Find the volume of the solid under the plane 3x+2y−z=0 and above the region enclosed by the parabolas y=x^2 and x=y^2.

Yuri [45]

The region in the x-y plane is the set of points

$R=\{(x,y)\mid0\le x\le 1,x^2\le y\le\sqrt x\}$

The height of the solid falls between the x-y plane (for which z = 0) and the equation of the plane, z = 3x + 2y.

So the volume is

$\displaystyle\int_0^1\int_{x^2}^{\sqrt x}\int_0^{3x+2y}\mathrm dz\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_0^1\int_{x^2}^{\sqrt x}(3x+2y)\mathrm dy\,\mathrm dx$

$=\displaystyle\int_0^1(3x^{3/2}+x-3x^3-x^4)\,\mathrm dx$

$=\displaystyle\frac65+\frac12-\frac34-\frac15=\boxed{\dfrac34}$

5 0

3 years ago

A marker bought for Rs 50 was sale at a profit of 5%. find the selling price.

ivanzaharov [21]

Answer:

The selling price would be Rs 52.5

Step-by-step explanation:

Rs 50 is the actual cost and the 5% profit will amount to Rs 2.5 (50*5%) so total total sales price would be Rs 52.5( Rs 50 + Rs 2.5)

Another way to calculate is (Rs 50 * 1.05) = 52.5

4 0

4 years ago

Read 2 more answers