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Licemer1 [7]
3 years ago
15

-3m-1<-10 or -4+2m<-14

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
8 0

Answer:

m>3 or m<-5

Step-by-step explanation:

First simplify -3m-1 < -10:

-3m < -9

m > 3 (switch direction of sign when dividing by negative number)

Then simplify -4+2m<-14:

2m<-10

m<-5

m>3 or m<-5

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A software distributor charges \$41$41dollar sign, 41 per license of a particular utility. The distributor offers a 10\%10%10, p
Alchen [17]

Answer:

1558

Step-by-step explanation:

The first 202020 licenses cost full price, which is \$41$41dollar sign, 41 each. Thus, the first 202020 licenses cost a total of \$41 \cdot 20 = \$820$41⋅20=$820dollar sign, 41, dot, 20, equals, dollar sign, 820.

Hint #2

The remaining licenses have a 10\%10%10, percent discount. That means they cost 90\%90%90, percent of the full price. Let's write 90\%90%90, percent in its decimal form, 0.90.90, point, 9, in order to multiply.

\qquad 0.9 \cdot \$41 = \$36.900.9⋅$41=$36.900, point, 9, dot, dollar sign, 41, equals, dollar sign, 36, point, 90

Hint #3

There are 40 - 20 = 2040−20=2040, minus, 20, equals, 20 licenses at the reduced price of \$36.90$36.90dollar sign, 36, point, 90. Thus, the remaining 202020 licenses cost a total of \$36.90 \cdot 20 = \$738$36.90⋅20=$738dollar sign, 36, point, 90, dot, 20, equals, dollar sign, 738.

Hint #4

To find the cost for all 404040 licenses, let's add the costs of the full price and discounted licenses.

\qquad \$820 + \$738 = \$1558$820+$738=$1558dollar sign, 820, plus, dollar sign, 738, equals, dollar sign, 1558

Hint #5

The business would pay \$1558$1558dollar sign, 1558 to buy the licenses.

3 0
3 years ago
Compare the surface area-to-volume ratios of the moon and mars. express your answer using two significant figures.
antoniya [11.8K]

we know that

For a spherical planet of radius r, the volume V and the surface area SA is equal to

V=\frac{4}{3} *\pi *r^{3} \\ \\ SA=4*\pi *r^{2}

The
ratio of these two quantities may be written as

SAV =\frac{(4*\pi*r^{2})}{(\frac{4}{3}*\pi*r^{3})}     \\  \\ SAV =\frac{3}{r}

we know

rMoon=1,738Km\\ rMars=3,397 Km

\frac{SAV Moon}{SAV Mars} =\frac{3}{rMoon} *\frac{rMars}{3} \\ \\ \frac{SAV Moon}{SAV Mars} =\frac{rMars}{rMoon} \\ \\ \frac{SAV Moon}{SAV Mars} =\frac{3,397}{1,738} \\ \\ \frac{SAV Moon}{SAV Mars} =1.9545

therefore

the answer is

1.9

5 0
3 years ago
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What is the series you are referring too?
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QUESTION 1
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Answer:

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