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Nat2105 [25]
3 years ago
6

You buy a Lily and an African violet on the same day.You are instructed to water the Lily every fourth day and water the voilet

every seventh day after taking them home.What is the first day on witch you will water both plants on the same day?How can I use this awnser to determine each of the next days you will water both plants on the same day?
Mathematics
1 answer:
max2010maxim [7]3 years ago
8 0
It will be on the 28th day
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SWEET T HAS 2 ORANGE PICKS FOR EVERY 5 GREEN. IF THERE ARE 21 PICKS IN ALL, HOW MANY PICKS ARE ORANGE?
IrinaVladis [17]

Answer:

For 21 picks, there are 6 orange

Step-by-step explanation:

orange: green   : total

2               5            2+5

2             5              7


If there are 21 picks, we need to divide by 7  to see how many times we need to multiply

21/7 = 3

Multiply everything by 3

orange: green   : total

2*3          5*3          7*3

6                 15           21

For 21 picks, there are 6 orange

6 0
2 years ago
Please help . I’ll mark you as brainliest if correct !!!!
pav-90 [236]
31-21=15
Answer: 15m
Answer check: 36+15=51✅
3 0
3 years ago
Read 2 more answers
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, -6), B(5, -6), C(5, -2)
max2010maxim [7]

Answer:

Step-by-step explanation:

Refer the answer of brainly.com/question/17115212

3 0
2 years ago
1. The number of rabbits on an island is increasing exponentially.
Zina [86]

Answer:

<em>There are approximately 114 rabbits in the year 10</em>

Step-by-step explanation:

<u>Exponential Growth </u>

The natural growth of some magnitudes can be modeled by the equation:

P=P_o(1+r)^t

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given two measurements of the population of rabbits on an island.

In year 1, there are 50 rabbits. This is the point (1,50)

In year 5, there are 72 rabbits. This is the point (5,72)

Substituting in the general model, we have:

50=P_o(1+r)^1

50=P_o(1+r)\qquad\qquad[1]

72=P_o(1+r)^5\qquad\qquad[2]

Dividing [2] by [1]:

\displaystyle \frac{72}{50}=(1+r)^{5-1}=(1+r)^{4}

Solving for r:

\displaystyle r=\sqrt[4]{\frac{72}{50}}-1

Calculating:

r=0.095445

From [1], solve for Po:

\displaystyle P_o=\frac{72}{(1+r)^5}

\displaystyle P_o=\frac{72}{(1.095445)^5}

P_o=45.64355

The model can be written now as:

P=45.64355(1.095445)^t

In year t=10, the population of rabbits is:

P=45.64355(1.095445)^{10}

P = 113.6

P\approx 114

There are approximately 114 rabbits in the year 10

5 0
2 years ago
Given the system of linear equations.
Degger [83]

Part(A):

To solve the system of Linear equations using Substitution:

x+y=7 \\ 2x+y=5

Consider the first equation, x+y=7 implies x=7-y

\mathrm{Subsititute\:}x=7-y

2\left(7-y\right)+y=5

14-2y+y=5

14-y=5

\mathrm{Subtract\:}14\mathrm{\:from\:both\:sides}

14-y-14=5-14

-y=-9

\mathrm{Divide\:both\:sides\:by\:}-1

y=9

\mathrm{For\:}x=7-y

\mathrm{Subsititute\:}y=9

x=7-9=-2.\mathrm{The\:solutions\:to\:the\:system\:of\:equationts\:are:}

y=9,\:x=-2

PArt(B): Use a graph to verify your answer to the system:

Using Desmos graphing calculator, graph the two equations.

8 0
3 years ago
Read 2 more answers
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