write an equation to represent the oxidation of an alcohol.
identify the reagents that may be used to oxidize a given alcohol.
identify the specific reagent that is used to oxidize primary alcohols to aldehydes rather than to carboxylic acids.
identify the product formed from the oxidation of a given alcohol with a specified oxidizing agent.
identify the alcohol needed to prepare a given aldehyde, ketone or carboxylic acid by simple oxidation.
write a mechanism for the oxidation of an alcohol using a chromium(VI) reagent.
The reading mentions that pyridinium chlorochromate (PCC) is a milder version of chromic acid that is suitable for converting a primary alcohol into an aldehyde without oxidizing it all the way to a carboxylic acid. This reagent is being replaced in laboratories by Dess‑Martin periodinane (DMP), which has several practical advantages over PCC, such as producing higher yields and requiring less rigorous reaction conditions. DMP is named after Daniel Dess and James Martin, who developed it in 1983.
This page looks at the oxidation of alcohols using acidified sodium or potassium dichromate(VI) solution. This reaction is used to make aldehydes, ketones and carboxylic acids, and as a way of distinguishing between primary, secondary and tertiary alcohols.
Oxidizing the different types of alcohols
The oxidizing agent used in these reactions is normally a solution of sodium or potassium dichromate(VI) acidified with dilute sulfuric acid. If oxidation occurs, the orange solution containing the dichromate(VI) ions is reduced to a green solution containing chromium(III) ions. The electron-half-equation for this reaction is
Cr2O2−7+14H++6e−→2Cr3++7H2O
In ionic bonds electrons are transferred from one species to another and the electrostatic attraction between oppositely charged ions gives rise to the ionic bond.
covalent bonds are when electrons are shared between 2 atoms.
the electronegativity difference between the atoms taking part in the bond will decide if its an ionic bond or covalent bond.
if the electronegativity difference is very large then ionic bond is formed. if the electronegativity difference is very low then covalent bond is formed
the electronegativity difference between H and S is very small therefore they form a covalent bond by sharing their electrons
correct answer is
2) electrons are shared to form a covalent bond
True; i<span>onic bonds result from high electronegativity differences</span>
Answer:
60 to 80
<h3>Explanation:</h3><h3> Because the interquartile range IQR</h3>
Q1 IS 25TH Percentile the Q3 75th percentile
Answer:
A
Explanation:
Hydrogen and chlorine need to be balanced. There is an equal amount of magnesium on each side
