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Masja [62]
3 years ago
10

What is an example of a physical change

Chemistry
2 answers:
ad-work [718]3 years ago
6 0
A physical change can be something like breaking into pieces. a physical change is when the chemical makeup is not changed. anything like corrosion, burning, or anything like that will be chemical.
igomit [66]3 years ago
3 0
Crushing can, breaking glass, boiling water, shredding paper
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Consider the formation of nitrogen dioxide from nitric
Temka [501]

Answer:

9 L

Explanation:

According to the question , the given reaction is -

2NO(g) + O₂(g)------->2NO₂(g)

Since ,

At STP ,

One mole of a gas occupies the volume of 22.4 L.

Hence , as given in the question -

9 L of NO , i.e .

22.4 L = 1 mol

1 L = 1 / 22.4 mol

9 L = 1 / 22.4  * 9 L = 0.40 mol

From the chemical reaction ,

The Oxygen is in excess , hence NO becomes the limiting reagent , and will determine the moles of product .

Hence ,  

2 moles of NO will produce 2 moles of NO₂.

Therefore ,

0.40 mol of NO will produce 0.40 mol of NO₂.

Hence , the volume of NO₂ can be calculated as -

1 mol = 22.4 L

0.40 mol = 0.40 * 22.4 L = 9 L

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3 years ago
One atom of silicon can properly be combined in a compound with
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B. two atoms of oxygen
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An astronomer studying planets outside our solar system has analyzed the atmospheres of four planets. Which of these planets’ at
Nata [24]

Answer: Planet A: 76% Nitrogen, 23% Oxygen, 1% Other

Explanation: Hope this helps!

3 0
3 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
goblinko [34]
 The balanced equation for

 Ca(OH)2  +  H3PO4→  Ca3(PO4)2  +  H2O    is

 3 Ca(OH)2  +2 H3PO4→  Ca3(Po4)2  +  6  H2O

3 moles of  Ca(OH)2  reacted with 2  moles of H3PO4  to  form  1 mole  of  Ca3(PO4)2   and  6  moles  of H2O
6 0
3 years ago
Read 2 more answers
12.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?
Zielflug [23.3K]

Answer: 7.693 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=0.63atm\\V_1=12.70L\\P_2=105kPa=1.04atm(1kPa=0.009atm)\\V_2=?

Putting values in above equation, we get:

0.63\times 12.70mL=1.04\times V_2\\\\V_2=7.693L

Thus new volume of the gas is 7.693 L

6 0
3 years ago
Read 2 more answers
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