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Masja [62]
3 years ago
10

What is an example of a physical change

Chemistry
2 answers:
ad-work [718]3 years ago
6 0
A physical change can be something like breaking into pieces. a physical change is when the chemical makeup is not changed. anything like corrosion, burning, or anything like that will be chemical.
igomit [66]3 years ago
3 0
Crushing can, breaking glass, boiling water, shredding paper
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Sn, Si, C

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3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4 H2O
liubo4ka [24]

24.25 moles of NO can be produced using 97 moles of HNO3.

<h3>What is balanced chemical equation?</h3>

Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Varied elements' atom counts in the reactants and products of unbalanced chemical equations are different.

3 Cu + 8HNO3 g → 3 Cu(NO3)2 + 2 NO + 4 H2O

The number of moles consumed can be calculated using comparing with coefficients in the balanced reaction .

So , from above eq we get that 8 moles of HNO3 are consumed to make 2 moles of NO.

⇒  8 HNO3⇔2 NO

⇒ 1 HNO3⇔ 1/4 NO

This means that for each mole of HNO3 produces 1/4 moles of NO.

So , for 97 moles of HNO3 , \frac{1}{4}  *97 moles of NO can be made,

So, total moles of NO made are 24.25 moles.

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3 0
2 years ago
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How is alkyne converted to acetone?
cricket20 [7]

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3 0
3 years ago
How much energy is required to vaporize 48.7 g of dichloromethane (CH2Cl2) at its boiling point, if its ΔHvap is 31.6 kJ/mol?
BartSMP [9]

Answer:

The answer is 18.12KJ is required to vaporise 48.7 g of dichloromethane at its boiling point

Explanation:

To solve the above question we have the given variable as follows

ΔHvap = heat of vaporisation of dichloromethane per mole = 31.6KJ/mole

However since the heat of vaporisation is the heat to vaporise one mole of dichloromethane, then, for 48.7 grams of dichloromethane, we have.

The number of moles of dichloromethane present = 48.7/84.93 = 0.573 moles

Therefore, the amount of heat required to vaporise 48.7 grams of dichloromethane at its boiling point is 31.6KJ/mole×0.573moles =18.12KJ

3 0
4 years ago
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