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MaRussiya [10]
3 years ago
8

What is the smallest degree of rotation that will map a 20-gon onto itself?

Mathematics
1 answer:
astraxan [27]3 years ago
7 0
360 / 20   =   <span>18°
i don't know if that is right</span>
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The gray figure has been transformed in different ways.
yanalaym [24]

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False ,false,true, true and true

Step-by-step explanation:

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3 years ago
Can somebody help me with these questions?
jarptica [38.1K]

Answer:

5. (3)

6. (1)

Step-by-step explanation:

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2 years ago
Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

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<em>% = </em><em>1</em><em>0</em>

7 0
2 years ago
Three more than six times a number is 33
Whitepunk [10]

Answer:

the number is 5

Step-by-step explanation:

6n + 3 = 33

6n = 30

n = 5

6 0
2 years ago
Two cars leave towns 300 kilometers apart at the same time and travel toward each other. One car's rate is 16 kilometers per hou
julia-pushkina [17]
The cars travel with constant speed, and the equations of movement of each one are,

x_1=v_1t

x_2=x_0-v_2t

Where v_1=16 Km/h, v_2 is unknown, x_0 is 300 kilomters. As they meet in 2 hours, then t=2 and x_1=x_2, so,

x=v_1t

x=x_0-v_2t

Solving for v_2,

v_2=x_0/t-v_1=134\ \ Km/h
6 0
3 years ago
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