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LiRa [457]
3 years ago
11

Solve the exponential equation for x

Mathematics
2 answers:
34kurt3 years ago
8 0

216 = 6^3

so

216 = 6^(4x + 11)

6^3 = 6^(4x + 11)

3 = 4x + 11

4x = 3 -11

4x = - 8

 x = -2

hichkok12 [17]3 years ago
8 0

Answer:

the value of x=-2

Step-by-step explanation:

216=6^{4x+11}

To solve for x  we need to make the same base on both sides

we need to get same base 6 on both sides of the equation.

216 can be written as 6 times 6 times 6 =6^3

6^3=6^{4x+11}

Both sides have same base, so we equate the exponents

3=4x+11

Subtract 11 on both sides

-8=4x

Divide both sides by 4

-2=x

So the value of x=-2

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10y + 10 =130 solve for y
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Answer: y=12

Step-by-step explanation:

10y+10=130

-10 -10

10y=120

—- ——

10. 10

Y=12

5 0
3 years ago
A certain marathon has had a wheelchair division since 1977. An interested fan wondered who is​ faster: the​ men's marathon winn
Dimas [21]

Answer:

A. The distribution of sample means of the differences will be approximately normal if there are at least 30 years of data in the sample​ and/or if the population of differences in winning times for all years is normal.

Step-by-step explanation:

In other to perform a valid paired test, one of the conditions required is that, data for both groups must be approximately normal. To attain normality, the population distribution for the groups must be normal or based on the central limit theorem, the sample size must be large enough, usually n > 30. Hence, once either of the two conditions are met, the paired sample will be valid.

8 0
3 years ago
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

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This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

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-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

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The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
2 years ago
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8 0
3 years ago
Ebony earned scores of 72 70, 81, 99, and 88 on five math tests. Determine her
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Let it be x

\boxed{\sf Average=\dfrac{Sum\:of\:terms}{No\:of\:terms}}

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\\ \sf\longmapsto x=498-410

\\ \sf\longmapsto x=88

6 0
3 years ago
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