Was the difference in the overall men's winner in the ages 70-74 group more less than 2 hours

s344n2d4d5 [400]

Y=-3x+5
the slope is negative because the line is going down from left to right
the y-intercept is 5 because that’s where the line crosses the y-axis

5 0

2 years ago

In the equation b= a-2, which is the independent variable and which is the dependent variable ? Explain???? need help i don't un

Nataliya [291]

A is independent while b is dependent.

This is because b is equal to a decreased by 2. Anytime a changes, then b does as well. B can only change in accordance with a.

7 0

3 years ago

The area of a rectangle is 42 m2, and the length is

MrRissso [65]

Answer:

length = 14 m

width = 7 m

Step-by-step explanation:

l = length

w = width

l = 2w - 8

w(2w - 8) = 42

2w² - 8w - 42 = 0

you can factor out a 2 to work with smaller numbers:

w² - 4w - 21 = 0

(w - 7)(w + 3) = 0

w = 7

'w' cannot equal a negative so we discount it as an answer

find length:

l = 2(7) - 8

l = 14 - 8 or 6m

6 0

3 years ago

How do I solve this?

Readme [11.4K]

Answer:

x ≈ -4.419

Step-by-step explanation:

Separate the constants from the exponentials and write the two exponentials as one. (This puts x in one place.) Then use logarithms.

0 = 2^(x-1) -3^(x+1)

3^(x+1) = 2^(x-1) . . . . . add 3^(x+1)

3×3^x = (1/2)2^x . . . . .factor out the constants

(3/2)^x = (1/2)/3 . . . . . divide by 3×2^x

Take the log:

x·log(3/2) = log(1/6)

x = log(1/6)/log(3/2) . . . . . divide by the coefficient of x

x ≈ -4.419

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A graphing calculator is another tool that can be used to solve this. I find it the quickest and easiest.

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<em>Comment on alternate solution</em>

Once you get the exponential terms on opposite sides of the equal sign, you can take logs at that point, if you like. Then solve the resulting linear equation for x.

(x+1)log(3) = (x-1)log(2)

x=(log(2)+log(3))/(log(2)-log(3))

4 0

2 years ago

Choose the correct answer below. A. Increasing the level of confidence has no effect on the interval. B. Increasing the level of

murzikaleks [220]

Answer:

$ME = t_{\alpha/2} \frac{s}{\sqrt{n}}$

And the width for the confidence interval is given by:

$Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}$

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval $t_{\alpha/2}$ would be higher and then the width of the interval would increase. So then the best answer for this case would be:

B. Increasing the level of confidence widens the interval.

Step-by-step explanation:

Let's assume that we have a parameter of interest $\mu$ who represent for example the true mean for a population. And we can construct a confidence interval in order to estimate this parameter if we know the distribution for the statistic let's say $\bar X$ and for this particular example the confidence interval is given by:

$\bar X \pm ME$

Where ME represent the margin of error for the estimation and this margin of error is given by:

$ME = t_{\alpha/2} \frac{s}{\sqrt{n}}$

And the width for the confidence interval is given by:

$Width =2ME=2t_{\alpha/2} \frac{s}{\sqrt{n}}$

And we want to see the effect if we increase the confidence level for a interval. On this case if we increase the confidence level then the critical value for the confidence interval $t_{\alpha/2}$ would be higher and then the width of the interval would increase. So then the best answer for this case would be:

B. Increasing the level of confidence widens the interval.

3 0

2 years ago