Three I think. Might be wrong
Suppose
is another solution. Then

Substituting these derivatives into the ODE gives


Let
, so that

Then the ODE becomes

and we can condense the left hand side as a derivative of a product,
![\dfrac{\mathrm d}{\mathrm dx}[x^5u]=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E5u%5D%3D0)
Integrate both sides with respect to
:
![\displaystyle\int\frac{\mathrm d}{\mathrm dx}[x^5u]\,\mathrm dx=C](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Bx%5E5u%5D%5C%2C%5Cmathrm%20dx%3DC)

Solve for
:

Solve for
:

So another linearly independent solution is
.
R(s+t) = rs + rt represents Distributive Property because r is multiplying s and t
i.e. ( r*s + r*t )
= rs + rt
So correct answer is Distributive Property.
hope this helps :)
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope intercept form as
y = mx + c
Where
m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)
The equation of the given line is
x + 2y = 4
2y = - x + 4
y = -x/2 + 4/2
y = - x/2 + 2
Comparing with the slope intercept form, slope = - 1/2
If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the given line.
Therefore, the slope of the line passing through (- 2, 1) is 2
To determine the intercept, we would substitute m = 2, x = - 2 and y = 1 into y = mx + c. It becomes
1 = 2 × - 2 + c = - 4 + c
c = 1 + 4 = 5
The equation becomes
y = 2x + 5
1/2 would work for the blank space
because as shown in the image you could relate it to a whole for each one and put it to 100 to figure out what the blank could be
the 0.20 can be converted to 1/5 so that way you can put everything into the 100 group