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Brums [2.3K]
3 years ago
11

Need this geometry answer

Mathematics
1 answer:
marta [7]3 years ago
5 0
See its a straight line and the angle of straight line is 180

so according to this

7x+x-4 = 180
8x = 184
x= 23

therefore angle DBC 23-4 = 19

SO 19 IS THE ANSWER
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Iii. Divide and simplify if possible.<br> 7)<br> 5V2u y2<br> V 18uv4<br> 8)<br> 3V 50x’y<br> V2.xy
Luden [163]
Ummm let’s see......

3xy(1/3)
7 0
3 years ago
Write the equations after translating the graph of y = | 1/2 x -2 | + 3 one unit to the right
spin [16.1K]

Using translation concepts, the equation of the graph is:

y = |0.5x - 2.5| + 3.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The function is:

y = |0.5x - 2| + 3.

When it is shifted one unit to the right, we have that x -> x - 1, hence:

y = |0.5(x - 1) - 2| + 3

y = |0.5x - 2.5| + 3.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

5 0
2 years ago
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
How you explain the can you compare how you feel right now with how you felt before we started with the relaxation activity? On
DochEvi [55]

Answer:

I would rate my feelings 4 on a scale of 5

Step-by-step explanation:

Before exercising I usually feel low and heavily laden with overwhelming thoughts and the feeling doesn't seem to leave except in engage in some form of activities that will take my time and consciousness of time.

Like exercising does take time and it's very engaging one wouldn't know the passage of time while doing some physical task.

It's always relaxing after engaging in physical exercise,I also see it as physical therapy for mental health.

8 0
3 years ago
What is 0.65×0.11 if you answer first ill make brainlyest
nadezda [96]

Answer:

0.0715

Step-by-step explanation:

Not much to explain

3 0
3 years ago
Read 2 more answers
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