We have that
<span>log10 E = 4.4 + 1.5<span>M
</span></span>E=<span>the released energy in Joules (J)
M= </span><span>earthquake measures---------- > 3.6
</span>log10 E = 4.4 + 1.5*3.6
log10 E = 9.8----------> E=10^(9.8)= 6.309573444 x10^9 J
<span>
the answer is </span>6.309573444 x10^9 J<span>
</span>
Answer: actual length = 45 ft
Explanation:
Scale drawn:
1/2 inch = 5ft
Meaning that if the drawing scale is 0.5 inch then the actual bus would be 5ft.
If the length of the drawn school bus is 4 1/2 inches. We can write:
1/2 = 5
4 1/2 = x
=> x = (5 x 4 1/2)/1/2
Or x = (5 x 4.5)/0.5
x = 22.5/0.5
x = 45
Therefore the actual length of the bus is 45 ft
-sqrt(36) = -6
Hope this helps :)
Answer:
-6/5
Step-by-step explanation:
solution;
let,the number be x,
product of <u>twice</u><u> </u><u>of</u><u> </u><u>x</u> and <u>six</u> = the <u>difference </u>
<u>difference of eleven times x and 6/5</u>
or, (2x×6)=(11×x)-(6/5)
or, 12x = 11x - 6/5
or, 12x - 11x = -6/5
therefore,x =-6/5
Therefore, the number required is (-6/5) whose product of twice a number and six is the same as the difference of eleven times the number and 6/5 .
Answer:
C
Step-by-step explanation:
