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Lerok [7]
2 years ago
14

WILL GIVE BRAINLIST IF U CAN ANSWER THESE 2!! QUESTIONS!! PLS

Mathematics
2 answers:
Korolek [52]2 years ago
7 0

Answer: d and the 2nd one is b

Step-by-step explanation:

luda_lava [24]2 years ago
6 0

Answer:

The following acountant that will earn the most interest is accountant D

Step-by-step explanation:

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Find the slope of the line through<br> 1) (15,3), (2,7)
Anuta_ua [19.1K]

Answer:

4/-13

Step-by-step explanation:

The formula for slope is y2-y1 over x2-x1.

5 0
3 years ago
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions
Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector \vec{v} in some vector space \mathbb R^n we have

\vec{v} = \langle a,b\rangle

This is the component form. I don't like that way. It is probably used in high school, but

\vec{v} =  \begin{pmatrix} a\\ b\\ \end{pmatrix}

is preferable because the inner product on \mathbb R^n is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as \vec{v} = 2i+2j

4.

For this question, I think you meant

vectors

\vec{u_1} = (-8, 12)

\vec{u_2}  = (13, 15)

Once

\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}

Considering that the dot product is

\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76

and the norm of \vec{u_1} is ||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}

and the norm of \vec{u_2} is ||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}

Thus,

\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}

\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)

3 0
2 years ago
In ∆ABC, m∠ACB = 90°, m∠A = 40°, and D ∈ AB such that CD is perpendicular to side AB. Find m∠DBC and m∠BCD.
podryga [215]

Answer:  ∠B = 50°

               ∠BCD = 40°

<u>Step-by-step explanation:</u>

ACB is a right triangle where ∠A = 40° and ∠C = 90°.

Use the Triangle Sum Theorem for ΔABC to find ∠B:

∠A + ∠B + ∠C = 180°

40° + ∠B + 90° = 180°

         ∠B + 130° = 180°

                  ∠B = 50°

BCD is a right triangle where ∠B = 50° and ∠D = 90°.

Use the Triangle Sum Theorem for ΔBCD to find ∠C:

∠B + ∠C + ∠D = 180°

50° + ∠C + 90° = 180°

         ∠C + 140° = 180°

                  ∠C = 40°

8 0
3 years ago
What percent of 965 is<br> 1932
ankoles [38]

Answer: It is 202.1 lol

4 0
3 years ago
Read 2 more answers
Let f(w) = 2w^3 - 5. What is f(4)?
ZanzabumX [31]
F(4) = 2(4)^3 -5
= 2(64) -5

= 128-5
= 123

Hope this helps!
3 0
3 years ago
Read 2 more answers
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