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3 years ago

X^3+2/3x^4-1/2x^2 integral

Mathematics

1 answer:

Irina-Kira [14]3 years ago

5 0

$\frac{2 {x}^{5} }{15} + \frac{ {x}^{4} }{4} - \frac{ {x}^{3} }{6} + c$

simplified form =

$\frac{ {x}^{3}(8 {x}^{2} + 15x - 10) }{60} + c$

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2*2<br><img src="https://tex.z-dn.net/?f=%20%5Ccos%28300%29%20" id="TexFormula1" title=" \cos(300) " alt=" \cos(300) " align="ab

ankoles [38]

Step-by-step explanation:

$\cos(300 \degree) \\ \\ = \cos(360 \degree - 60\degree) \\ \\ = \cos( 60\degree) \\ \\ = \frac{1}{2} \\ \\ \huge \orange{ \boxed{ \therefore \: \cos(300 \degree) = \frac{1}{2} }}$

7 0

3 years ago

Triangle J K L is shown. Angle J K L is 120 degrees and angle K L J is 40 degrees. The length of K L is 2 and the length of J L

Veseljchak [2.6K]

Answer:

$k \approx 5$ units$

Step-by-step explanation:

In Triangle JKL

$\angle K=120^\circ\\\angle L=40^\circ\\KL=2\\JL=k$

We want to determine the approximate value of k using the law of sines.

$\angle J+\angle K+\angle L=180^\circ $ (Sum of angles in a \triangle)\\\angle J+120^\circ+40^\circ=180^\circ \\\angle J=180^\circ-(120^\circ+40^\circ)=20^\circ$

Using Law of Sines

$\dfrac{k}{\sin K} =\dfrac{j}{\sin J} \\\dfrac{k}{\sin 120} =\dfrac{2}{\sin 20} \\k=\sin 120 \times \dfrac{2}{\sin 20}\\k=5.06\\k \approx 5$ units$

7 0

3 years ago

Read 2 more answers

Your grocery bill before taxes was $265.24. You have to pay 7.3% sales tax. How much is your total grocery bill?

tamaranim1 [39]

Answer:

$284.60

Step-by-step explanation:

7.3% of $265.24 = 19.36252,

So the tax is $19.36.

19.36 + 265.24 = 284.60

So the total grocery bill is $284.60.

6 0

3 years ago

Read 2 more answers

Let u = 〈1,5〉 and v = 〈3, −2〉. Write each vector in component form and draw an arrow to represent the vector.

Alexxx [7]

Answer:

a. 〈4,3〉

b. 〈-2,7〉

c. 〈11,4〉

Step-by-step explanation:

a. u + v

〈1,5〉 + 〈3, −2〉

〈1+3,5-2〉

〈4,3〉

b. u - v

〈1,5〉 - 〈3, -2〉

〈1-3,5-(-2)〉

〈-2,7〉

c. 2u + 3v

2*〈1,5〉 + 3*〈3,-2〉

〈2*1,2*5〉 + 〈3*3,3*(-2)〉

〈2,10〉 + 〈9,-6〉

〈2+9,10-6〉

〈11,4〉

To draw the vectors, let's put them on the origin (0,0), so let's draw the line until the point of its component form, with an arrow. The vectors are shown below.

7 0

3 years ago

find the height of a pyramid with a volume of 960 in^3 if the base is a square with a side length of 12 in.

slava [35]

The volume of a square pyramid is equal to:
Volume = a^2 (h/3)

In order for us to get the height, we need to substitute the values.
<span>Volume = a^2 (h/3)
</span>960 = 12^2 (h/3)
960 = 144h/3
960 = 48h
h = 20 in.

So the height is equal to 20 inches.

7 0

3 years ago