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miss Akunina [59]
4 years ago
7

What is the answer!!

Mathematics
2 answers:
Cloud [144]4 years ago
5 0

Answer:

∠ G = 121°

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 given angles and equate to 180

x + 3x + 25 + x - 5 = 180 , that is

5x + 20 = 180 ( subtract 20 from both sides )

5x = 160 ( divide both sides by 5 )

x = 32

Thus

∠ G = 3x + 25 = 3(32) + 25 = 96 + 25 = 121°

FromTheMoon [43]4 years ago
4 0

Answer:

121

Step-by-step explanation:

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Please Help,
musickatia [10]
X=6 Z=8 so X:Z =. 6/8 So 2 goes into both 6 and 8 so divide numerator and denominator by 2 which = 3/4
4 0
3 years ago
Read 2 more answers
11z/16+7z/8=5/16 as a decimal
babunello [35]
11z/16+7z/8=5/16
(11z+14z)/16=5/16
25z=5
z=5/25=1/5
4 0
3 years ago
4. The area of the parallelogram<br>is 81.9 in? What is the height​
ipn [44]

Answer 96in2

Step-by-step explanation:

formula to find area = base x height

substitute the values

= 10 x 9

= 90 cm2

7 0
3 years ago
What are the solution(s) of x squared minus 4 = 0? x = negative 4 or x = 4 x = negative 2 or x = 2 x = 2 x = 4
frosja888 [35]

Answer:

Step-by-step explanation:

The expression is

x^2 - 4

This is a quadratic expression.

To find the solution, we will equate the the expression to zero. It becomes

x^2 - 4 = 0

Add 4 to the left hand side of the equation and the right hand side of the equation. It becomes.

x^2 - 4 + 4 = 0 + 4

x^2 = 4

Take square root of the right hand side of the equation and left hand side of the equation. It becomes

√x^2 = √4

x = ± 2

x = 2 or x = - 2

7 0
3 years ago
Read 2 more answers
rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4
OleMash [197]

Answer:

The standard form is  8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of  y⁴  is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f  is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is  2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

                                8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

<em>The degree of given polynomial is '5'</em>

<em>The co-efficient of  y⁴  is '-17'</em>

<em>   </em>

5 0
3 years ago
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