Answer:
hey
Step-by-step explanation:
Answer:
2,5
Step-by-step explanation:
2 to the right and 5 up
Answer:
The point
is not a solution of the system of inequalities
Step-by-step explanation:
we have
-----> inequality A
-----> inequality B
we know that
If a ordered pair is a solution of the system of inequalities
then
the ordered pair must be satisfy the inequalities of the system
Verify
For 
substitute the value of x and the value of y in the inequalkity A and in the inequality B
Inequality A

-------> is not true
therefore
The point
is not a solution of the system of inequalities
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
You press the thing that look like a paper clip