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2 years ago

7

In a triangle RSTV, RS=5.3cm and ST=4.1 find perimeter of RSTV

1 answer:

Luba_88 [7]2 years ago

7 0

Is that a with 4 vertices ,,,check your question

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Only the math gods can write this 50 PT proof!

fredd [130]

Answer:

because the 1st corner and the 2nd corner is places in a straight line which the total agle is 180° so since the 1st corner has same angle as the 13th one the 14th is must be have same angle as the 2nd corner. so that the 1st corner + the 14th corner is equal as 180°

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2 years ago

Which of the following numbers could not be represent a probability

e-lub [12.9K]

[0,1] could not be used to represent a probability.

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2 years ago

In this exercise, we are conducting many hypothesis tests to test a claim. Assume that the null hypothesis is true. If 400 tests

Brums [2.3K]

Answer:

Since the null hypothesis is true, finding the significance is a type I error.

The probability of the year I error = level of significance = 0.05.

so, the number of tests that will be incorrectly found significant is computed as follow: 0.05 * 100 = 5

Therefore, 5 tests will be incorrectly found significant given that the null hypothesis is true.

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2 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

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2 years ago

Amanda's computer weighs 20 ounces. How many pounds does it weigh?

Natali5045456 [20]

Answer: 1.25

Step-by-step explanation:

Convert it lol I don’t know how to say it? But also you can look it up if needed

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2 years ago

Read 2 more answers