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Nimfa-mama [501]

2 years ago

6

the distance from kevins home to his school is 2 kilometers. adrian lives 750 meters from the same school. how much closer does

adrian live next to the school than kevin

1 answer:

notsponge [240]2 years ago

5 0

2km=2000m
2000m -750m=1250m thats the answer

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According to the graph, which range value corresponds to a domain value of 2?

Mekhanik [1.2K]

Answer:

D

Step-by-step explanation:

Simply put, domain means the x value and range means the y value.

<em><u>The question asks for the corresponding range (y-value) for domain (x-value) of 2. </u></em>

Looking at the graph, x value of 2 corresponds to y value of 4. So the answer is 4.

Correct answer is D

5 0

3 years ago

Read 2 more answers

Which expressions are equivalent to the one below. Check all that apply. 16^x

madam [21]

$A.\ 4^x\cdot4^x=4^{x+x}=4^{2x}\qquad\text{used}\ a^n\cdot a^m=a^{n+m}\\\\B.\ 4^{2x}=(4^2)^x=16^x\qquad\text{used}\ (a^n)^m=a^{nm}\\\\C.\ 4^2\cdot4^x=4^{2+x}\\\\D.\ (4\cdot4)^x=16^x\\\\E.\ 4\cdot4^{2x}=4^{1+2x}\\\\F.\ 4\cdot4^x=4^{1+x}\\\\Answer:\ \boxed{B.\ and\ D.}$

3 0

3 years ago

Can someone help me with this please?

11111nata11111 [884]

The perimeter is
$2(2z+3z-3)=44$
$\Rightarrow 2(5z-3)=44$
$\Rightarrow 10z-6=44$
$\Rightarrow 10z=50$
$\Rightarrow z=5$

The length of AB is
$3z-3=3(5)-3=15-3=12$

6 0

3 years ago

According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h

andreyandreev [35.5K]

Answer:

The graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph $f(x)=x^2-4x+3$

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation $f(x)=x^2-4x+3$ the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, $f(x)=x^2-4x+3=0$

This is a quadratic equation, $x^2-4x+3=0$

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

$x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0$

$\Rightarrow x(x-1)-3(x-1)=0$

$\Rightarrow (x-3)(x-1)=0$

Using zero product property, $a\cdot b=0 \Rightarrow a=0\ or \ b=0$

$\Rightarrow (x-3)=0$ or $\Rightarrow (x-1)=0$

$\Rightarrow x=3$ or $\Rightarrow x=1$

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

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3 years ago

Can someoneone help me with please i have to sent it today

ser-zykov [4K]

Answer:

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Step-by-step explanation:

Hope you like it xD It is not 100% finished so probably you can finish it, i wrote an introduction for you) good luck

8 0

2 years ago