1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
loris [4]
3 years ago
11

What is the remainder for the synthetic division problem below?

Mathematics
2 answers:
Tcecarenko [31]3 years ago
6 0
The full answer would be x^2 + 8x + 16 + (54/(x-3)). Therefore, the remainder would be A. 54.

Hope this helps!
antoniya [11.8K]3 years ago
4 0

Answer:

The remainder is 54

Step-by-step explanation:

we have to find the remainder for the synthetic division problem.

The steps are:

Step 1 : Bring the leading coefficient below.

Step 2 : Multiply the number in the division box with the number brought down and put the answer in next column.

Step 3 : Add the two numbers and write the result in the bottom of the row.

Step 4 : Repeat steps 3 and 4 until we reach to last column.

The division shown in attachment.

Option A is correct.

You might be interested in
4. Calcula la rapidez promedio de un perro que
wlad13 [49]

Answer:

5 m/s

Step-by-step explanation:

7 0
3 years ago
What does inversely proportional mean​
Assoli18 [71]
If one value is inversely proportional to another then it is written using the proportionality symbol in a different way. Inverse proportion occurs when one value increases and the other decreases. For example, more workers on a job would reduce the time to complete the task. They are inversely proportional.
7 0
2 years ago
The foci of an ellipse can be outside the ellipse.<br><br> True or false?
DanielleElmas [232]
False

foci of an ellipse cannot be outside the ellipse
5 0
3 years ago
Read 2 more answers
Ricardo uses 1-centimeter cubes to build a tower. Write an expression for the volume of the tower. What is the volume
snow_lady [41]
The answer to your question would be 20
7 0
2 years ago
Please help ill give whoever answers the best the brainliest answer :0
Greeley [361]

Expression (5x² - 2x + 7), (\frac{1}{5}x^3 -\frac{7}{2}x^2 -2) and (y⁵ - √(5y²) + 7) are polynomials.

<h3>What is a polynomial ? </h3>

A polynomial is a type of algebraic expression where exponents of all variables are whole number.

1) 5x² - 2x + 7

Since there are no variables raised to negative or fraction exponents,

the expression is a polynomial.

2) \frac{1}{5}x^3 -\frac{7}{2}x^2 -2

Since there are no variables raised to negative or fraction exponents,

the expression is a polynomial.

3) y⁵ - √(5y²) + 7

This can be re-written as

y^5-(\sqrt{5})y+7

Since there are no variables raised to negative or fraction exponents,

the expression is a polynomial.

4) \frac{y^3}{3} -\sqrt{y} +2

This can be re-written as

\frac{1}{3}y^2 -y^{1/2}+2

Since variable y is raised to a fraction exponent,

the expression is not polynomial.

Therefore, expression (5x² - 2x + 7), (\frac{1}{5}x^3 -\frac{7}{2}x^2 -2) and (y⁵ - √(5y²) + 7) are polynomials.

Learn more about polynomials here: brainly.com/question/17822016

#SPJ1

3 0
1 year ago
Other questions:
  • What fraction of an hour is 42 minutes? Give your answer in its simplest form
    7·1 answer
  • I need help on this look at picture above. Intercepts. I need help ASAP.
    12·2 answers
  • Wholesale cost of a telescope: $199.50; Markup: 50%, Discount: 30%,
    15·1 answer
  • Which of the following is a true statement?
    5·1 answer
  • Five-sixths of the thirty students passed their test. How many student did not pass
    11·1 answer
  • For which equations is x = 9 a possible solution? Check all that apply.
    12·2 answers
  • What is a horseshoe crab?
    6·1 answer
  • Loxlor<br><img src="https://tex.z-dn.net/?f=10%20%5Ctimes%2010" id="TexFormula1" title="10 \times 10" alt="10 \times 10" align="
    9·1 answer
  • Solve -4 b + 2 = 18.<br><br> b =
    12·2 answers
  • PLZ PLZ PLZZZZZZ HELP ME IMMEDIATLEY
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!