First, find the slope (m) =
=
=
= 
Now plug in ONE of the points and the slope into the point-slope equation:
y - y₁ = m(x - x₁); where (x₁, y₁) is the chosen point.
y - 5 =
(x - 1) (I used (1,5) as the chosen point)
3(y - 5) = x - 1
3y - 15 = x - 1
3y -14 = x
-14 = x - 3y → x - 3y = -14
Answer: x - 3y = -14
the length of segment AB is 13
Answer:
x = 5
Step-by-step explanation:
Using the fact that line segments AB and BC are parts of the whole line segment AC, we can write the following equation:
AB + BC = AC
Now, using the given values, we can substitute in for the equation and solve for x:
AB + BC = AC
9 + 2x - 5 = x + 9
2x + 4 = x + 9
x = 5
Thus, we have found that for these sets of equations for these line segments, our value for x should be 5.
Cheers.