Answer:
Adrian's adaptive immune system remembered the antigens from the virus. so he becomes immune to it.
Explanation:
Answer:
<em>Bacteria can obtain energy and nutrients by performing photosynthesis, decomposing dead organisms and wastes, or breaking down chemical compounds. Bacteria can obtain energy and nutrients by establishing close relationships with other organisms, including mutualistic and parasitic relationships.</em>
Explanation:
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Cancer is a mutation that occurs during the cell cycle, usually when it develops and grows it means the mutation was able to go through the cycle undetected at checkpoints so the cell was not destroyed by the lysosomes.
Eukaryotes are the<span> type of cells that typically do not contain cilia or a flagella.
The ones that do are called prokaryotes.</span>
<u>Answer:</u>
Q: Which skeletal system <u>disorder</u> might she be suffering from?
A: <u>Osteoporosis</u>
Q: What <u>techniques</u> could be used to diagnose her condition?
A: <u>Bone mineral density (BMD) test</u> or <u>dual energy X-ray absorptiometry (DXA) scan</u>
Q: What treatments are available?
A: Medication, healthy food.
<u>Explanation:</u>
<u>The vertebral discs between vertebrae could shrink with age</u>. Therefore, a height loss up to 1-inch is normal. However, if the height loss is more then it is possibly due to <u>osteoporosis</u>.
A <u>bone mineral density test</u>, also known as <u>dual energy X-ray absorptiometry</u> scan, is a well-adapted test to measure the amount of calcium and other minerals in the bones. It uses <u>X-rays</u> to measure the content of calcium and thus strength of bones.
A person who is already suffering from osteoporosis should be treated with <u>medicine</u> right away so that it <u>stops</u> further <u>deterioration of the bones</u> and <u>avoid any future bone fractures</u>. Further, it can be handled by <u>eating a healthy diet</u> and <u>supplements</u> such as <u>vitamins D</u>. In case some of the bones/vertebrae are <u>already fractured</u>, <u>surgical approaches</u> might be necessary.