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ololo11 [35]
3 years ago
5

I need help please ASAP i will mark branlist

Mathematics
1 answer:
gavmur [86]3 years ago
5 0
It's B!------------------------------
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The value of two numbers if their sum is 11 and their difference is 1
Nataly_w [17]

Answer:

So What is the question?

Step-by-step explanation:

3 0
3 years ago
400 meters of fencing . Twice as long as it is wide , what is the area
NNADVOKAT [17]

Answer:

The area is 13,3 squared meters

Step-by-step explanation:

The 400 meters of fencing is the perimeter of the area. We know that:

perimeter = 2 (length + width)

or

P = 2 (l+w)

We also know that the length is twice the width, hence:

l = 2w

Substituting this information in the perimeter equation:

P = 2 (2w + w)

P = 4w+2w

P = 6w

w = P/6

Now, the area is defined as:

A = l*w

Therefore,

A = 2*w*w

A = 2 * w^2

Putting the w =P/6 in the previous equation

A = 2 * (P/6)^2

A = 2 * P^2/36

A = P^2/12

And substituting the value of P and doing the math,

A = 13, 333 period 3 which we need to round to 13,3 which is the total number of significant digits given

6 0
4 years ago
A particle moves along the x–axis so that at time t its position is given by x(t) = (t+1)(t–3)3. For what values of t is the vel
rosijanka [135]

I'll assume that's an exponent at the end there:

x(t) = (t+1)(t-3)^3

The first derivative gives the velocity.  The second derivative gives the acceleration; increasing velocity is the same as positive acceleration.  So we want to find when the second derivative is positive.

Let's see if we can use d(uv) = u\, dv + v\, du to avoid multiplying this out.

x'(t) = 3 (t+1)(t-3)^2 + (t-3)^3

That worked; let's do it again:

x''(t) = 3( 2(t+1)(t-3) + (t-3)^2) + 3(t - 3)^2

x''(t) = 3(t-3) ( 2(t+1)  + (t-3) + (t - 3) ) = 3(t-3)(4t-4)=12(t-1)(t-3)

That's a nice parabola.  It's zero or negative for 1 \le t \le 3 so positive everywhere else:

Answer: Increasing velocity when t < 1 or t > 3


4 0
3 years ago
:
bazaltina [42]

Answer:

16 feet

Step-by-step explanation:

2 x Pi(3.14159....) x 2.5

6 0
4 years ago
How much would she have eaten after eight weeks?
Kamila [148]

Answer:

4 packages of gum in 8 weeks

Step-by-step explanation:

1/2 each week

1/2 x 8 = 4

7 0
3 years ago
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