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3 years ago

NEED HELP QUICKLY! PICTURE BELOW!

Mathematics

1 answer:

ollegr [7]3 years ago

5 0

Answer:

Step-by-step explanation:

Let me know if this is correct!

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Can someone help me with this please

stellarik [79]

Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign

Step 1: subtract 2x from each side

2x - 7y - 2x = 19 - 2x

This cancels out the 2x on the left, giving us

-7y = 19 - 2x

Step 2: divide both sides by -7

$\frac{-7y}{-7}$ = $\frac{19}{-7}$ + $\frac{-2x}{-7}$

This gives us

y = -19/7 + 2x/7

That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.

When x = -3

y = -19/7 + 2x/7

y = -19/7 + 2(-3)/7

y = -19/7 - 6/7

y = -25/7

When x = 0

y = -19/7 + 2x/7

y = -19/7 + 2(0)/7

y = -19/7

When x = 3

y = -19/7 + 2x/7

y = -19/7 + 2(3)/7

y = -19/7 + 6/7

y = -13/7

Hope that helps! Feel free to ask if I can help with anything else :)

7 0

2 years ago

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.