Given:
Dimension of box is 7 in, 13 in and 4 in.
To find:
Area of the smallest piece of paper
Solution:
Area of the rectangular box = length × width × height
= 7 × 13 × 4
Area of the rectangular box = 364 in³
Area of the rectangular box = Area of the gift paper to wrap the box
Therefore the area of the smallest piece of paper is 364 in³.
11/14-n/4=4/14 subtract 11/14 from both sides...
-n/4=-7/14 multiply both sides by -4
n=28/14
n=2
Answer:
x=6
y=1
Step-by-step explanation:
3x=18, so when you divide 3x by 3 to get x alone, you also divide the other side and 18 divided by 3 is 6. now you know that x equals 6. then you plug x back into either equation to solve for y. I chose to plus into x-3y=3. it would read 6-3y=3. you then subtract 6 from both sides and get that -3y=-3. therefore when you divide both sides by -3, you get that y=1
Answer: B
Step-by-step explanation:
3x - 4 = 11
add 4 to both sides so it cancels out
3x = 15
Now divide by 3
x = 5