Answer:
Therefore the depth of the water is changing at the instant when the water in the tank is 9 cm deep at rate / min.
Step-by-step explanation:
Given that,
Radius of the cone(r)= 6 cm
Height of the cone (h)= 12 cm
The volume of the cone is (V)
Putting
Differentiating with respect to t
....(1)
Given that water is drained out of tank at the rate 3 / min.
It means the rate change of volume is 3 / min that is
Putting the value of in equation (1)
To find the rate of the depth of water changing at 9 cm depth, we need to put h=9 cm in the above equation.
/ min.
Therefore the depth of the water is changing at the instant when the water in the tank is 9 cm deep at rate / min.
Unit rate in this case would be pages per minute so divide (5/8)pages÷(2/3)minute.
Dividing a fraction can be done as multiplying by the reciprocal.
(5/8)·(3/2)=15/16pages per minute or 0.9375 pages/min.
You will subtract these top 2
and this bottom one is your ANSWER
Answer:
1.5
Step-by-step explanation: