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kipiarov [429]
4 years ago
6

State the domain and range and determine if it's a function? Domain: Range: Function?

Mathematics
1 answer:
kramer4 years ago
8 0

Step-by-step explanation: Let's first write the coordinates of each point.

When finding the coordinates of a

given point, be very careful with your signs.

On the x-axis, left means negative and right means positive

and on the y-axis, down means negative and up means positive.

The points in this problem are (-1, -2), (4, -2), (1, 1), (2, 3).

The domain is the set of all x-coordinates.

So here, the domain or D = {-1, 4, 1, 2}.

The range is the set of all y-coordinates.

So here, the range is {-2, 1, 3}.

Notice that I only listed the 1 once.

We only need to mention it once in our range.

Finally, let's determine if it' a function.

If none of the x-coordinates repeat, it's a function.

Since none of them do repeat, it's a function.

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ElenaW [278]

Answer: it’s 3.5

Step-by-step explanation:

5 0
3 years ago
Can help me for homework pleas
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Hey You!

32 / 8 = 4

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6 0
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Elanso [62]
The answer is D. 6 squareroot of 2
6 0
3 years ago
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20 points!!!
Inga [223]

Answer:

82

Step-by-step explanation:

We are given that a graph which shows the number of beads used for varying cord lengths.

The graph

y=2.52x+1.61

We have to find the number of beads that she can used for cord length 32 in.

Substitute the value x=32

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y=2.52(32)+1.61=82.25

After round to unit place then, we get

y=82

Hence, the best estimate she can used  for number of beads =82

Answer: 82

7 0
3 years ago
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Sum and difference tan(135+30)
Mumz [18]
\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\sin y\cos x}{\cos x\cos y-\sin x\sin y}=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

So,

\tan(135^\circ+30^\circ)=\dfrac{\tan135^\circ+\tan30^\circ}{1-\tan135^\circ\tan30^\circ}

You should know that \tan135^\circ=-1 and \tan30^\circ=\dfrac1{\sqrt3}

Putting everything together,

\tan(135^\circ+30^\circ)=\dfrac{-1+\dfrac1{\sqrt3}}{1-(-1)\left(\dfrac1{\sqrt3}\right)}=\dfrac{1-\sqrt3}{\sqrt3+1}=\sqrt3-2
7 0
4 years ago
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