The vertex form of the equation of a parabola is X=(y-3)^2+41. What is the standard form of the equation?

Mathematics

1 answer:

Alisiya [41]3 years ago

4 0

Answer: x=Y^2-6y+50

For APEX

You might be interested in

What integer can be represented by 13 positive tiles and 26 negative tiles? 39 –13 –8 13

Alex17521 [72]

Answer:

-13 #markasbrainliest

3 0

3 years ago

A triangle has a base of ten inches and an altitude of fourteen inches what is the area

OleMash [197]

The answer is 70 in^2
$(10 \times 14) \div 2 = 140 \div 2 = 70$

good luck

4 0

4 years ago

Can someone helpp me with this i will give brainlest :)

marta [7]

Answer:

Step-by-step explanation:

1slice=280 and 6 slices so 280x6 so 0x6=0 then 80x6=6+6x4=48x10=480
then 200x6= 6x2=12x100=1200

add all 0+480+1200=1680

sry i'm not used to showing work i usually do it all in my head

8 0

1 year ago

Solve the following equation for x. x2 + 8x + 7 = 0 A. x = -1; x = -7 B. x = 1; x = -7 C. x = 1; x = 7 D. x = -1; x = 7

BabaBlast [244]

So the right answer is of option A.

Look at the attached picture

Hope it will be helpful to you..

5 0

3 years ago

Read 2 more answers

(a) Explain what is wrong with the following ‘proof’:Statement:IfRis symmetric and transitive, thenRis reflexive."Proof":Suppose

barxatty [35]

Answer:

Step-by-step explanation:

Recall that, in this case, the subset of X for which R is defined is called the domain of R. The mistake occurs when we assume that the domain R is the whole set X, but it could happen that R is not defined for some elements of X.

Recall the following example:

X = {2,4,6}.

We can define R as follows {(2,2), (4,4), (2,4), (4,2)}. We can easily check that this is a transitive and symmetric relation, but since we don't have the element (6,6) it fails to be reflexive.

8 0

4 years ago