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3 years ago

11

Determine weather 3x-4y+7=3y+1 is a linear equation

1 answer:

mezya [45]3 years ago

6 0

Answer:

yes because 3x-7 does not have a degree higher than 1

Step-by-step explanation:

If the degree were to be 2 it would be considered quadratic.

In this case it is just x (1) so it is linear.

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Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago

9/5 - (-6/10)<br> Khan academy needs either exact fraction or exact decimal

mixer [17]

Answer:

Exact fraction: 6/5

Exact Decimal: 1.2

5 0

3 years ago

Read 2 more answers

What is 2 1 to 4 ÷ 3 to 4

babunello [35]

Answer:

........

Step-by-step explanation:

.......................

3 0

3 years ago

Is rectangle EFGH the result of a dilation of rectangle ABCD with a center of dilation at the origin? Why or why not?

katrin [286]

Answer:

the answer is b bro

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

s2008m [1.1K]

The students on the right hand side had better overall results

There were less people on the left hand side of the room this affects the average even with the right hand side having two zeros, another thing which the left hand side didn’t have.

Hope I helped

3 0

2 years ago